Your list of numbers needs a bit of clarification.
You wrote: <span>.9,1.1,.10 38 and .10299
I have to make some assumptions here, and to ask whether you meant the following:
</span><span>.9, 1.1, .1038 and .10299
If so, now's the time to look for the smallest and the largest of these numbers. The smallest is 0.10299:
smallest
</span>
0.10299
<span>0.1038
0.9
1.1
</span>.9, 1.1, .1038 and .10299
If my list disagrees with yours, please ensure that you have copied down these four numbers correctly and then try again (on your own) to order them correctly from smallest to largest.
There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
it would be a, b, and c because if you look at the question and the answers, 3 of the four answers match the 3 of the 4 coordinates
