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daser333 [38]
2 years ago
14

An empty 6-gal water jug weighs 0.5 lb. With 3 c of water inside, the jug weighs 2 lb. Which equation models the jug’s weight y

when it contains x cups of water?
Mathematics
2 answers:
kiruha [24]2 years ago
7 0
J = jug
J = 0.5x + 0.5
leva [86]2 years ago
5 0

Answer:

The equation can be modeled be : y = 0.5 + 0.5 × x

Step-by-step explanation:

Weight of empty 6-gal water jug = 0.5 lb

After filling 3 cups of water inside, the weight of jug becomes 2 lb

So, increased weight after filling 3 cups of water = 1.5 lb

So, weight of 1 cup of water = 0.5 lb

Now, weight of the jug be y and water filled be x cups

Hence, The equation can be modeled be :

y = 0.5 + 0.5 × x

Thus, this is our required equation.

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Whats is 3/5 as a percent
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3 years ago
Will award brainliest for the correct answer!
Alex787 [66]

Answer:

<h2><em>4x³</em></h2>

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8x⁴y⁴ = 4×2×x³×x¹×y⁴ = 4x³×(2xy⁴)

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Then the greatest common factor is of the two terms 8x⁴y⁴ and 12x³z² is:

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4 0
2 years ago
De moirve's <br> (√3-i ÷ √3+i)^6 = 1
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(√3 - <em>i </em>) / (√3 + <em>i</em> ) × (√3 - <em>i</em> ) / (√3 - <em>i</em> ) = (√3 - <em>i</em> )² / ((√3)² - <em>i</em> ²)

… = ((√3)² - 2√3 <em>i</em> + <em>i</em> ²) / (3 - <em>i</em> ²)

… = (3 - 2√3 <em>i</em> - 1) / (3 - (-1))

… = (2 - 2√3 <em>i</em> ) / 4

… = 1/2 - √3/2 <em>i</em>

… = √((1/2)² + (-√3/2)²) exp(<em>i</em> arctan((-√3/2)/(1/2))

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[(√3 - <em>i </em>) / (√3 + <em>i</em> )]⁶ = exp(-6<em>iπ</em>/3) = exp(-2<em>iπ</em>) = 1

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