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ohaa [14]
3 years ago
7

Line segment DCOE is a diameter of circle O, line segment AB is a chord of the circle, and line segment OD is perpendicular to l

ine segment AB at C. If AB=8 and OC=3, find OB
Mathematics
1 answer:
Harman [31]3 years ago
3 0
i did 8+3 #not sure if thats what u would do or not)
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Step-by-step explanation:

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Given that the measure of ∠x is 60°, and the measure of ∠y is 90°, find the measure of ∠z.
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I really need help
Zielflug [23.3K]

Answer:

The answer is (C)

The equation of the circle is (x + 4)² + (y - 6)² = 81

Step-by-step explanation:

* To find the equation of the circle you need to know

  the center of the circle and the length of its radius

* The rule of the equation of the circle is:

  (x - h)² + (y - k)² = r²

  Where x and y is a general point on the circle,

  h and k are the coordinates of the center of the circle

  and r is the radius of the circle

∵ The center of the circle is (-4 , 6)

∵ The radius of the circle is 9

∴ (x - -4)² + (y - 6)² = 9²

∴ ( x + 4)² + (y - 6)² = 81

∴ The answer is (C)

3 0
4 years ago
If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle
stira [4]

Answer:

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<u>Step-by-step explanation:</u>

Given points end  Points are p(-3,-2) and q( 1,6)

<em>The distance of two points formula</em>

P Q = \sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2}   }

P Q = \sqrt{1 - (-3)^{2} + ((6 -(-2))^{2}   }

P Q = \sqrt{16+64} = \sqrt{80}

<em>The diameter 'd' = 2 r</em>

                       2 r = √80

                            = \sqrt{16 X 5}

                           = 4 \sqrt{5}

                     <em> r =  2√5</em>

<em>Mid-point of two end points </em>

<em>                        </em>(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )<em></em>

<em>                                               = (-1 ,2)</em>

<em>Mid-point of two end points = center of the circle</em>

<em>                                     (h,k) = (-1 , 2)</em>

                 

The equation of the circle

           (x -h )² +(y-k)² = r²

<em>          (x -(-1) )² +(y-(2))² = (2(√5))²</em>

<em>         x² + 2 x + 1 + y² - 4 y + 4 = 20</em>

<em>          x² + 2 x + y² - 4 y  = 20 -5</em>

<em>           x² + 2 x + y² - 4 y  = 15</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<em>                  </em>

6 0
4 years ago
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