3 years ago

Look at the graph shown:

Mathematics

1 answer:

gayaneshka [121]3 years ago

8 0

The answer would be y= 4x + 4 over 3
Because your slope would be 4/3 and the formula you needed was y=mx+b

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timofeeve [1]

1. x = 1/ ( $\sqrt{3} - \sqrt{2)}$ = $\sqrt{3}+ \sqrt{2}$ ;
( $\sqrt{x} -1/ \sqrt{x} )^{2} = x + 1/x - 2 =$ =

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3 years ago

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This is a number like 10 101,000 and so on it it is the result of using only a 10 as a factor

BaLLatris [955]

Answer: it is called the powers of ten

Step-by-step explanation:

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3 years ago

There are 80 sixth graders, 90 seventh graders, and 70 eighth graders at your school. Every student gets entered in a raffle. Wh

Effectus [21]

The answer is a 42.857% chance which is 3/8

I'm glad to help, I hope this was helpful

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3 years ago

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Please help mee! <33 y+4=-4(x+2) in standard form! <3

Pachacha [2.7K]

Answer:

y = -4x - 12

Step-by-step explanation:

y + 4 = -4(x + 2)

y = -4x -8 - 4

y = -4x - 12

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2 years ago

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If you need $8000 to travel to Europe after you graduate in 4 year. How much would your monthly deposits need to be if your acco

lina2011 [118]

$\bf \qquad \qquad \textit{Future Value of an ordinary annuity}\\
\left. \qquad \qquad \right.(\textit{payments at the end of the period})
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]$

$\bf \qquad 
\begin{cases}
A=
\begin{array}{llll}
\textit{accumulated amount}\\
\end{array}\to &
\begin{array}{llll}
8000
\end{array}\\
pymnt=\textit{periodic payments}\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12\\
t=years\to &4
\end{cases}$

$\bf 8000=pymnt\left[ \cfrac{\left( 1+\frac{0.05}{12} \right)^{12\cdot 4}-1}{\frac{0.05}{12}} \right]
\\\\\\
\cfrac{8000}{\left[ \frac{\left( 1+\frac{0.05}{12} \right)^{12\cdot 4}-1}{\frac{0.05}{12}} \right]}=pymnt\implies \cfrac{8000}{\frac{\left( \frac{241}{240} \right)^{48}-1}{\frac{1}{240}}}=pymnt
\\\\\\
\cfrac{8000}{53.0148852}\approx pymnt\implies 150.9010152318\approx pymnt$

6 0

3 years ago