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4 years ago

List and define all the ways to pay for college

2 answers:

8 0

There are many ways you can pay for your college tuition. First, you can find a part time job. Most colleges are gracious to students, especially working students. So they would usually allow installments on the tuition fee, with some added terms. If not, there would always be university scholarships if you happen to be doing well in your studies. There also is the option of student loans for those students who need help in paying for the tuition.

mario62 [17]4 years ago

3 0

There is many way but here are some.you can get a job and star saving up your money.

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Waterway Industries purchased a depreciable asset for $837300 on January 1, 2018. The estimated salvage value is $84000, and the

murzikaleks [220]

Answer:

$222,100

Explanation:

Cost = $837,300

Residual value = $84,000

Useful life = 9 years

Now,

Annual straight line depreciation = $\frac{Cost-Residual Value}{Useful life}$

Annual straight line depreciation = $\frac{837,300 - 84,000}{9}$

Annual straight line depreciation = $\frac{753,300}{9}$

Annual straight line depreciation = $83,700

Accumulated depreciation for three years i.e., 2018, 2019 and 2020 would be:

Accumulated depreciation = 3 × $83,700

Accumulated depreciation = $251,100

Book value (at the end of year 2020) = Cost - Accumulated depreciation

Book value (at the end of year 2020) = $837,300 - $251,100

Book value (at the end of year 2020) = $586,200

Revised useful life = 5 years

No. years asset has been used = 3 years

Remaining useful life = 2 years

Revised salvage value = $142,000

Therefore, depreciation expense for the remaining three year would be:

Revised depreciation expense = $\frac{Book value at the end of 2020 - Revised residual Value}{Remaining useful life}$

Revised depreciation expense = $\frac{586,200 - 142,000}{2}$

Revised depreciation expense = $\frac{444,200}{2}$

Revised depreciation expense = $222,100

5 0

3 years ago

Jason opened up a steak and seafood restaurant. when jason opened his business, his primary objective was to?

damaskus [11]

The primary objective of Jason when he opened up a steak and seafood restaurant was to change the cattle and seafood industry.

<h3>What is a business?</h3>

Business involves the process of buying as well as the selling of different goods as well as products, which can also been seen in the food industry.

It should be noted that ,in the case of jason, The primary objective of Jason when he opened up a steak and seafood restaurant was to change the cattle and seafood industry.

Learn more about business at:

brainly.com/question/24448358

#SPJ1

4 0

2 years ago

A catalog company that receives the majority of its orders by telephone conducted a study to determine how long customers were w

Oksi-84 [34.3K]

The waiting time at which 10 percent of the people would continue to hold is given as 2.3

<h3>How to solve for the waiting time</h3>

We have to solve for X ~ Exponential(λ).

then E(X) = 1/λ = 3,

= 0.3333

Remember that the cumulative distribution function of X is F(x) = 1 - e^(-λx). ; x is equal to the time in over case

For 10 percent of the people we would have a probability of

10/100 = 0.1

we are to find

P(X ≤ t)

= 1 - e^(0.3333)(t) = 0.1

Our concern is the value of t

Then we take the like terms

1-0.1 = e^(0.3333)(t)

1/0.9 = e^(0.3333)(t)

t = 3 * ln(1/0.9)

= 0.3157

5 0

2 years ago

Tiago makes three models of camera lens. Its product mix and contribution margin per unit follow:

Hatshy [7]

Answer:

Tiago

1. Weighted-average contribution margin per unit:

Weighted-Average

Contribution margin

per unit

Lens A $9.5

Lens B 12.0

Lens C 15.05

2. Break-even point (units) for each = Fixed cost/Contribution margin per unit

= Lens A = 4,921 units

Lens B = 6,233 units

Lens C = 4,349 units

3. Units to generate a profit target: = (FC+ Target Profit)/Contribution per unit

Lens A = 6,842 units

Lens B = 8,667 units

Lens C = 6,047 units

Explanation:

a) Data and Calculations

Percentage of Contribution Weighted-Average

Unit sales Margin per unit Contribution margin per unit

Lens A 25 % $ 38 $9.5

Lens B 40 30 12.0

Lens C 35 43 15.05

Fixed Costs of $187,000:

Lens A = 25% of $187,000 = $46,750

Lens B = 40% of $187,000 = $74,800

Lens C = 35% of $187,000 = $65,450

Break-even point (units) for each = Fixed cost/Contribution margin per unit

= Lens A = $46,750/$9.5 = 4,921 units

Lens B = $74,800/$12 = 6,233 units

Lens C = $65,450/$15.05 = 4,349 units

Profit of $73,000

Lens A = 25% of $73,000 = $18,250

Lens B = 40% of $73,000 = $29,200

Lens C = 35% of $73,000 = $25,550

Units to generate a profit target: = (FC+ Target Profit)/Contribution per unit

Lens A = ($46,750 + $18,250)/$9.5 = 6,842 units

Lens B = ($74,800 + $29,200)/$12 = 8,667 units

Lens C = ($65,450 + $25,550)/$15.05 = 6,047 units

3 0

3 years ago

The following are budgeted data: January February March Sales in units 15,900 21,800 18,900 Production in units 18,900 19,900 17

NISA [10]

Answer:

20,300 pounds

Explanation:

<u>Purchases Budget for February - Pounds</u>

Material required in Production 19,900

Add Opening Materials Inventory (19,900 x 20%) 3,980

Total 23,880

Less Closing Materials Inventory (17,900 x 20%) (3,580)

Budgeted Purchases 20,300

Therefore,

Purchases of raw materials for February would be budgeted to be 20,300 pounds

8 0

3 years ago