Find the coordinates of the vertices of the figure after the given transformation. translation: (x, y)→(x - 4, y + 4) A) J'(1, 0
), N'(5, 0), M'(5, 3), P'(2, 5) B) J'(-2, 5), N'(2, 5), M'(2, 2), P'(-1, 0) C) J'(-3, 4), N'(1, 4), M'(1, 1), P'(-2, -1) D) J'(-1, 0), N'(-5, 0), M'(-5, -3), P'(-2, -5)
1 answer:
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Answer:
The difference in the amount of interest she would have to pay for the two loans is $1,400
Step-by-step explanation:
The amount of loan Holly is taking out, P = $10,000
The choices available for the loan are;
1) Loan duration, T₁ = 4-year
Interest rate, R₁ = 4%
2) Loan duration, T₂ = 6-year
Interest rate, R₂ = 5%
For the first choice, we have;
The simple interest, I, given by the formula;
For the second choice, we have;
The simple interest, I, given by the formula;
The difference, D, in the amount of interest she would have to pay for the two loans is therefore;
D = I₂ - I₁ = $3,000 - $1,600 = $1,400
The difference in the amount of interest she would have to pay for the two loans = D = $1,400.
Answer:
The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.
Step-by-step explanation:
Given : The position of an object along a vertical line is given by , where s is measured in feet and t is measured in seconds.
To find : What is the maximum velocity of the object in the time interval [0, 4]?
Solution :
The velocity is rate of change of distance w.r.t time.
Distance in terms of t is given by,
Derivate w.r.t. time,
It is a quadratic function so its maximum is at vertex of the function.
The x point of the function is given by,
Where, a=-3, b=6 and c=7
As 1 lie between interval [0,4]
Substitute t=1 in the function,
Th maximum velocity is 10 ft/s.
Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.