Ask question

Ask question

All categories

3 years ago

6

By rounding each number to 1 significant figure,

1 answer:

luda_lava [24]3 years ago

4 0

Answer:

Step-by-step explanation:

1. 8.2 * 6.7 / 0.46

2. 54.94 / 0.46

3. 119.434783

4: 120

You might be interested in

Solve for x 8 is to 64 as 2 is to X

KIM [24]

8 is to 64 as 2 is to 16

x=16

5 0

2 years ago

Read 2 more answers

What is the equation in point slope form of the line passing through (0,5) and (-2,11)

IRISSAK [1]

The equation of the line passing through $(x_1,y_1)$ and $(x_2,y_2)$ is

$\frac{x-x_1}{y-y_1} =\frac{x_2-x_1}{y_2-y_1}$ . Here

$\frac{y_2-y_1}{x_2-x_1}$ is the slope of the line.

Substituting numerical values, the equation of the line is

$\frac{x-0}{y-5} =\frac{-2-0}{11-5} \\ \frac{x}{y-5} =-\frac{1}{3} \\ 3x=5-y\\ 3x+y=5$

The equation of the line is $3x+y=5$

6 0

2 years ago

How to get the volume of a answer

Eduardwww [97]

Mass* length * breadth

3 0

3 years ago

Michael’s weight can be represented by the expression 72x^5. Al’s weight can be represented by the expression 9x^7.

podryga [215]

Answer:

a) $\frac{72x^5}{9x^7}$

b) $=\frac{8}{x^2}$

c), Yes; $8x^2$

Step-by-step explanation:

Michael's Weight: $72x^5$

Al's weight: $9x^7$

a) Ratio of Michael's weight to Al's weight: $\frac{72x^5}{9x^7}$

b) This ratio simplifies to: $\frac{8\times 9x^5}{9x^5\timesx^2}$

$=\frac{8}{x^2}$

c) Yes, If the exponent in each expression were negative, then we have:

Ratio of Michael's weight to Al's weight: $\frac{72x^{-5}}{9x^{-7}}$

This ratio simplifies to: $8x^{-5--7}=8x^2$

The two ratios are not the same.

3 0

3 years ago

What is the best approximation of the length of segment QS? (Note: cos 80° = 0.17)

matrenka [14]

Answer: $QS=11.8cm$

Step-by-step explanation:

1. You have the following information:

- The lenght of $RS$ is 2 centimeters.

- The angle m∠S=80°.

- Cos80°=0.17

2. Therefore, you can calculate the lenght of the segment $QS$ as following:

$cos80=\frac{adjacent}{hypotenuse}$

$adjacent=2cm\\hypotenuse=QS\\cos80=0.17$

3. Substitute values and solve for $QS$ :

$0.17=\frac{2cm}{QS}\\QS=\frac{2cm}{0.17} \\QS=11.76cm$

4. To the nearest tenth:

$QS=11.8cm$

6 0

3 years ago