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8_murik_8 [283]
2 years ago
6

with vertices D(2, 5), E(6, 4), and F(3, 3), is reflected across the line y=x A student determined one of the vertices on the im

age to be (2, –5). Evaluate the student’s answer
Mathematics
1 answer:
pochemuha2 years ago
8 0
The point (2, -5) would not be one of the correct vertices of the reflected shape.

When we reflected a shape across the line y=x, we just replace the x's with y's and y's with x's.

Our new points are (5, 2) (4, 6) and (3, 3). None of the points contain negative numbers.
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If f(x) = 2x2 and g(x)= x2 + 2x, which expression represents f(g(x))?
andre [41]

Answer:

f(g(x)) = 2(x^2 + 2x)^2

f(g(x)) = 2x^4 + 8x^3 + 8x^2

Step-by-step explanation:

Given;

f(x) = 2x^2

g(x) = x^2 + 2x

To derive the expression for f(g(x)), we will substitute x in f(x) with g(x).

f(g(x)) = 2(g(x))^2

f(g(x)) = 2(x^2 + 2x)^2

Expanding the equation;

f(g(x)) = 2(x^2 + 2x)(x^2 + 2x)

f(g(x)) = 2(x^4 + 2x^3 + 2x^3 + 4x^2)

f(g(x)) = 2(x^4 + 4x^3 + 4x^2)

f(g(x)) = 2x^4 + 8x^3 + 8x^2

Hope this helps...

7 0
3 years ago
Three coins are flipped,what is the Probability of getting one HEAD and two TAILs?
san4es73 [151]
The probability of getting at most 2 tails is 7/8
7 0
3 years ago
The function f(t) = 33 sin (pi over 2t) − 20 models the temperature of a periodic chemical reaction where t represents time in h
Gennadij [26K]
The given function is
f(t) = 33 sin( \frac{ \pi }{2} t) - 20
with
t = time, hours
f = temperature, °C


Because the maximum and minimum values for the Sine function are +1 and -1 respectively,
The maximum value of f  = 33 - 20 = 13.
The minimum value of f = -33 - 20 = -53. 

The period, T,  is given by
\frac{2 \pi }{T} = \frac{ \pi }{2} \\ \\ T=4

Answer:
Maximum: 13°;  Minimum: -53°;  period: 4 hours
4 0
3 years ago
Radioactive Waste The rate at which radioactive waste is entering the atmosphere at time t is decreasing and is given by Pe^-kt,
Dmitry_Shevchenko [17]

Answer:

\displaystyle{\int^{\infty}_0 {50e^{-0.04t}}\, dt}=1250

Step-by-step explanation:

Given:

T =\displaystyle{\int^{\infty}_0 {Pe^{-kt}} \, dt}

where,

T = total amount of waste

P = 50, the initial rate

k = 0.04

t = time

T =\displaystyle{\int^{\infty}_0 {50e^{-0.04t}} \, dt}

now we need to solve this integral!

T =\displaystyle{50\int^{\infty}_0 {e^{-0.04t}} \, dt}

T = \left|50\left(\dfrac{e^{-0.04t}}{-0.04}\right)\right|^{\infty}_0

T = \left|-1250e^{-0.04t}\right|^{\infty}_0

T = (-1250e^{-0.04(\infty)})-(-1250e^{-0.04(0)})

when any number has a power of negative infinity it is 0. because: a^-{\infty} = \dfrac{1}{a^{\infty}} = \dfrac{1}{\infty} = 0, like something being divided by a very large number!

T = (-1250(0))-(-1250e^0)

T = 1250

this is the total amount of waste

6 0
2 years ago
Use the table in the previous question where 5 peppers cost $2.25 to answer the below.
Ronch [10]
If five peppers cost $2.25 then you could buy 40 peppers with $18 dollars and have $2 left over
3 0
2 years ago
Read 2 more answers
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