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8_murik_8 [283]
2 years ago
6

with vertices D(2, 5), E(6, 4), and F(3, 3), is reflected across the line y=x A student determined one of the vertices on the im

age to be (2, –5). Evaluate the student’s answer
Mathematics
1 answer:
pochemuha2 years ago
8 0
The point (2, -5) would not be one of the correct vertices of the reflected shape.

When we reflected a shape across the line y=x, we just replace the x's with y's and y's with x's.

Our new points are (5, 2) (4, 6) and (3, 3). None of the points contain negative numbers.
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Simone invests 1200 into two savings accounts. One account earns 4% annual interest and the other earns 5.9% annual interest. At
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Answer: He invested $350 at 4% and $850 at 5.9%

Step-by-step explanation:

Let x represent the amount which he invested in the account earning 4% interest.

Let y represent the amount which he invested in the account earning 5.9% interest.

Simone invests 1200 into two savings accounts. One account earns 4% annual interest and the other earns 5.9% annual interest. This means that

x + y = 1200

The formula for determining simple interest is expressed as

I = PRT/100

Considering the account earning 4% interest,

P = $x

T = 1 year

R = 4℅

I = (x × 4 × 1)/100 = 0.04x

Considering the account earning 5.9% interest,

P = $y

T = 1 year

R = 5.9℅

I = (y × 5.9 × 1)/100 = 0.059y

At the end of 1 year, Simon earned 64.15 in interest. it means that

0.04x + 0.059y = 64.15 - - - - - - - - -1

Substituting x = 1200 - y into equation 1, it becomes

0.04(1200 - y) + 0.059y = 64.15

48 - 0.04y + 0.059y = 64.15

- 0.04y + 0.059y = 64.15 - 48

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7 0
3 years ago
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2) Standard deviation
The standard deviation is given by:
\sigma =  \sqrt{ \frac{1}{N} \sum (x_i-\mu)^2 }
where \mu is the mean, that we already found at point 1), and N=4. Substituting data, we have:
\sigma =  \sqrt{ \frac{1}{4} ((-0.56)^2+(18.52)^2+(-13.99)^2+(-3.96)^2) } =
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3 years ago
4. Solve the system using substitution.
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