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Tju [1.3M]
3 years ago
9

HELP HELP HELP!!!!!!!

Mathematics
1 answer:
tresset_1 [31]3 years ago
5 0

Answer:

sorry i am struggling the same

Step-by-step explanation:

2+2=4

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a 120 watt light bulb uses about 0.1 kilowatt of electricity per hour. if electricity costs 0.20 per kilowatt hour, how much doe
Allushta [10]
A 120 watt light-bulb is a 0.120 kilowatt light bulb.

In one hour, it uses 0.120 kilowatt-hour of energy.

If electrical energy costs $0.20 per kilowatt hour, then that light bulb costs

        (0.120 kilowatt-hour / hour) x (0.20 dollar / kilowatt-hour) =

                            (0.120 x $0.20 / hour)  =  

                                       $0.024 / hour  =  <span>2.4¢  per hour </span>
5 0
4 years ago
Massimo spent $90. riding the bus. Each bus ride cost $2.50. Write and solve an equation to determine how many times Massimo rod
Varvara68 [4.7K]

Answer:

$90 ÷ $2.50 = 36

Massimo rode the bus 36 times.


Please mark brainliest. Have a great day!

5 0
3 years ago
A rectangle has a diagonal of 277 centimeters and a length of 252cm. How long is the width?
Crank

Answer:

width = 115 cm

Step-by-step explanation:

width² = 277² - 252²

width² = 76729 - 63504 = 13225

width = 115 cm

7 0
3 years ago
Read 2 more answers
Whats the area of a circle with a circumference of 31.4unit
marin [14]

Answer:

78.54

Step-by-step explanation:

first you have to divided 31.4 by 3.14 to get your diameter so you can get your radius. 31.4 divided by 3.14 equals 10 and 10 divided by 2 equals 5 which is you radius.  The formula for area for a circle is πr². 5 squared is 25 and 3.14 times 25 equals 78 .54 which is your answer.

8 1
3 years ago
A room has three lightbulbs. Each one has a 30% probability of burning out within the month. Write the probability as a percenta
lesantik [10]

Answer:

97.3%

Step-by-step explanation:

Let the three bulbs be A, B and C respectively.

Let P(A) denote the probability that the first bulb will burn out

Let P(B) denote the probability that the second bulb will burn out

Let P(C) denote the probability that the third bulb will burn out

Now, we are told that Each one has a 30% probability of burning out within the month.

Thus;

P(A) = P(B) = P(C) = 30% = 0.3

Now, probability that at the end of the month at least one of the bulbs will be lit will be given as;

P(at least one bulb will be lit) = 1 - (P(A) × P(B) × P(C))

P(at least one bulb will be lit) = 1 - (0.3 × 0.3 × 0.3) = 0.973 = 97.3%

3 0
4 years ago
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