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3 years ago

HELP HELP HELP!!!!!!!

Mathematics

1 answer:

tresset_1 [31]3 years ago

5 0

Answer:

sorry i am struggling the same

Step-by-step explanation:

2+2=4

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Two integers have a sum of -44 and a difference of 22. The greater of the two integers is

Leni [432]

Answer:

-11

Step-by-step explanation:

The generic solution to ...

a + b = sum
a - b = difference

Can be found by adding the two equations:

(a+b) + (a-b) = (sum) + (difference)

2a = (sum + difference)

a = (sum + difference)/2

___

Our particular solution is ...

a = (-44 +22)/2 = -11

The greater of the two numbers is -11.

___

The other number is -33.

5 0

3 years ago

Graph the points (0,-2), (4,0) and (2,0). If you want to create a parallelogram, which of the following points should used for t

MariettaO [177]

( 2 , - 2 )

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8 0

2 years ago

Mr. Weiss is ordering parts for his wheelchair on the Internet. The website is offering 15% off orders over $250.

aleksandrvk [35]

Answer:

$230.65

Step-by-step explanation:

$179 marked down by 35 % = $116.35

computer mount= $99

cell holder= $56

total= $271.35

marked down by 15% = $230.65 (230.6475)

6 0

2 years ago

If you complete the square for the equation 3x2 - 5x = 2, the answer is ( x + 5/6 )2 = 97/36.

Ray Of Light [21]

Answer:

True

Step-by-step explanation:

4 0

2 years ago

The probability that an American CEO can transact business in a foreign language is .20. Twelve American CEOs are chosen at rand

NNADVOKAT [17]

Answer with Step-by-step explanation:

We are given that

The probability that an American CEO can transact business in foreign language=0.20

The probability than an American CEO can not transact business in foreign language= $1-0.20=0.80$

Total number of American CEOs chosen=12

a. The probability that none can transact business in a foreign language= $12C_0(0.20)^0(0.80)^{12}$

Using binomial theorem $nC_r(1-p)^{n-r}p^r$

The probability that none can transact business in a foreign language= $\frac{12!}{0!(12-0)!}(0.8)^{12}=(0.8)^{12}$

b.The probability that at least two can transact business in a foreign language= $1-P(x=0)-p(x=1)=1-((0.8)^{12}+12C_1(0.8)^{11}(0.2))=1-((0.8)^{12}+12(0.8)^{11}}(0.2))$

c.The probability that all 12 can transact business in a foreign language= $12C_{12}(0.8)^0(0.2)^{12}$

The probability that all 12 can transact business in a foreign language= $\frac{12!}{12!}(0.2)^{12}=(0.2)^{12}$

5 0

3 years ago