The distance traveled by Mr.Nersin = 4 miles
The time for which Mr.Nersin rode first = 1/2 hour
The time for which Mr.Nersin rode after a short rest = 1/10 hour
Then
The total time for which Mr.Nersin rode = (1/2) + (1/10) hour
= (5 + 1)/10 hour
= 6/10 hour
= 3/5 hour
So
Average speed of Mr. Nersin = Distance traveled / Time taken
= 4/(3/5) miles/hour
= (4 * 5)/3 miles/hour
= 20/3 miles/hour
= 6 2/3 miles/hour
= 6.67 miles per hour
So the average speed at which Mr.Nersin traveled is 6 2/3 or 6.67 miles per hour.
Complete question :
A 12-foot by 15-foot patio is increased by placing a stone border around the patio. The width of the border is the same all around the patio.The perimeter of the patio after it is expanded is 74 feet. The equation which represents x, the width of the border is 2[(12+2x)+15+2x)]=74. What is the width of the border?
1) 2 1/2 feet
2) 3 feet
4) 5 feet
5) 8 1/2 feet
Answer:
2.5
Step-by-step explanation:
Solving for X in the perimeter equation :
2[(12+2x)+15+2x)]=74
Open the bracket
2[(12 + 2x + 15 + 2x)] = 74
2(27 + 4x) = 74
54 + 8x = 74
8x = 74 - 54
8x = 20
x = 20/8
x = 2.5
Hence, width fo border = 2.5
Answer:
12
<h3>
Step-by-step explanation:</h3>
-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10
count the spaces between the two numbers
<h2 />
Answer:
B. Perimeter of a square and
C. Side length of a square
Step-by-step explanation:
if n= side length of square then
- Area of square is
- Perimeter of a square is 4×n
- diagonal length of a square is
× n
Thus,
Perimeter of square can be expressed as
×diagonal length of a square
Side length of a square can be expressed as
×diagonal length of a square
but Area of square is
×n×diagonal length of a square
As a Result, Area of square is <em>also dependent of the value n</em>, wheras in other cases it is <em>a proportion of diagonal length of a square</em>
