Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.
A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'
B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)
C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)
D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n
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* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.
The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
Use Compound Interest Monthly Formula:
A = P(1 + r/n)^nt
A = Future Amount
P = Initial Amount
r = Interest rate
n = monthly
= 12 months
t = 15
In this case:
P = 2500
r = 7.8%
n = 12 months
t = 15 years
7.8% = 7.8/100
= 0.078
2500(1 + 0.078/12)^12(15)
= 8024.54 —> Final Answer.
Step-by-step explanation:
Note: Question does not indicate if probability required is for weight to exceed or below 3000 lbs. So choose appropriate answer accordingly (near the end)
Using the usual notations and formulas,
mean, mu = 3550
standard deviation, sigma = 870
Observed value, X = 3000
We calculate
Z = (X-mu)/sigma = (3000-3550)/870 = -0.6321839
Probability of weight below 3000 lbs
= P(X<3000) = P(z<Z) = P(z<-0.6321839) = 0.2636334
Answer:
Probability that a car randomly selected is less than 3000
= P(X<3000) = 0.2636 (to 4 decimals)
Probability that a car randomly selected is greater than 3000
= 1 - P(X<3000) = 1 - 0.2636 (to 4 decimals) = 0.7364 (to 4 decimals)
Answer:
x < 12
Step-by-step explanation:
So 8 times the sum of a number and 26 is less than 304. To find the number, lets write a equation where the "number" is x.
8 times the sum of a number and 26 can be written as 8 * x+26, however since the sum of x and 26 are being multiplied, we write this as 8(x+26). Since 8 times the sum of a number and 26 is less than 304, we set 8(x+26) to < 304. This gives us our equation:
8(x+26) < 304
Lets start to solve for x by dividing by 8, giving us:
x+26 < 38
Now lets isolate x by subtracting 26 from both sides, which gives us our answer:
x < 12
So x is less than 12.
Hope this helps!
