1. Find the H.C.F. of 4x2y3 and 6xy2z.
Solution:
The H.C.F. of numerical coefficients = The H.C.F. of 4 and 6.
Since, 4 = 2 × 2 = 22 and 6 = 2 × 3 = 21 × 31
Therefore, the H.C.F. of 4 and 6 is 2
Answer:
how to solve 2x+2y=2 , -4x+4y=12
this is solving equations using substitution .... i have ALOT more but i juss dnt get this stuff
2x + 2y = 2 -4x + 4y = 12
x + y = 1
x = 1 - y
-4x + 4y = 12
-4(1 - y) + 4y = 12
(-4 + 4y) + 4y = 12
-4 + 8y = 12
8y = 16
y = 2
2x + 2y = 2
2x + 2(2) = 2
2x + 4 = 2
2x = -2
x = -1
Check.
-4x + 4y = 12
-4(-1) + 4(2) = 12
4 + 8 = 12
Answer: x = -1 and y = 2
Step-by-step explanation:
Answer:
Dave got the entire office a loaf of bread and it has 11 slices. There where 4 other people that got the bread including dave how many slices would each person get?
Step-by-step explanation:
just divide 11 by 4
Answer:
18
Step-by-step explanation:
I think the answer would be 89
