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Elenna [48]
3 years ago
6

A rectangle with perimeter 198 cm is divided into five congruent rectangles. What is the perimeter of one of the five congruent

rectangles?
Mathematics
1 answer:
Yanka [14]3 years ago
3 0
P = 198 cm

P/5 = 198 cm/5

P/5 = 39.60 cm

I believe this is the perimeter of one of the 5 congruent rectangles.
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Triangle ABC had a perimeter 18 cm
Anna007 [38]

Answer:

Use pythagoreum theorem to determine whether it is or isn't since I'm not really sure myself but here's my calculations.

Step-by-step explanation:

We need to find AC.

Picture a triangle called ABC. AB is one side and BC the other while AC is the hypotenuse.

AC=

ac =  \sqrt{ab ^{2}  +  {bc}^{2} } \\ ac = \sqrt{ {7}^{2} }  +  {3}^{2}  \\ ac =  \sqrt{49 + 9}  \\ ac =  \sqrt{58 }  \\ ac = 7.6

Round up the 7.6 to a whole number and you get AC=8. To get perimeter of a triangle simply add the sides together to get 18.

Not really sure about my answer but hope this helped.

5 0
3 years ago
Given that the value of x is between 0 and 360 degrees (0 and 360
Brums [2.3K]

Answer:

  • 150° and 210°
  • 0

Step-by-step explanation:

It is convenient to memorize the trig functions of the "special angles" of 30°, 45°, 60°, as well as the way the signs of trig functions change in the different quadrants. Realizing that the (x, y) coordinates on the unit circle correspond to (cos(θ), sin(θ)) can make it somewhat easier.

__

<h3>20.</h3>

You have memorized that cos(x) = (√3)/2 is true for x = 30°. That is the reference angle for the 2nd-quadrant angle 180° -30° = 150°, and for the 3rd-quadrant angle 180° +30° = 210°.

Cos(x) is negative in the 2nd and 3rd quadrants, so the angles you're looking for are

 150° and 210°

__

<h3>Bonus</h3>

  You have memorized that sin(π/4) = √2/2, and that cos(3π/4) = -√2/2. The sum of these values is ...

  √2/2 + (-√2/2) = 0

_____

<em>Additional comments</em>

Your calculator can help you with both of these problems.

The coordinates given on the attached unit circle chart are (cos(θ), sin(θ)).

6 0
2 years ago
How to subtract a negative fraction from a positive fraction?
ikadub [295]
Let's take an example to illustrate this case:

<span>positive fraction = 2/7
</span>
<span>negative fraction = - 3/5

Now we need to subtract  </span><span>- 3/5 from 2/7

Right?

2/7 - (-3/5) = 2/7 + 3/5

here we need to unify the denominators as follows:

the lowest common factor between 7 and 5 is 35
2/7 = 10/35
3/5 = 21/35

Now back to </span><span>2/7 + 3/5:

</span><span><span>2/7 + 3/5 = 10/35 + 21/35 = (10+21)/35 = 31/35

That's it




Hope that helps you</span>
</span>
8 0
3 years ago
You have a garden in your backyard that measures 15 meters by 20 meters. You want to place stepping stones around the perimeter
Anettt [7]

Answer:

0.5 m

Step-by-step explanation:

Given that the dimensions of the garden are 15 meters by 20 meters.

The area of the new garden (original garden + stone placed around the perimeter) is 336m².

Let d be the width of the border having stepping stones as shown in the figure. The shaded region in the figure is the area having stepping stones.

The area including the shaded region = (15+2d)(20+2d) m^2

\Rightarrow 336  = (15+2d)(20+2d) \\\\\Rightarrow 336  = 300+ 70 d +4d^2 \\\\\Rightarrow 4d^2 +70d+300-336=0 \\\\\Rightarrow 4d^2 +70d-36=0 \\\\\Rightarrow 2d^2 +35d-18=0 \\\\\Rightarrow 2d^2 +36d-d-18=0 \\\\\Rightarrow (2d-1)(d+18)=0 \\\\\Rightarrow (2d-1)=0, \; or \; (d+18) \\\\\Rightarrow d= 0.5\;or -18 \\\\

As the width of the stone border can't be a negative value, so taking the positive value.

Hence, the width of the stone border is 0.5 m.

So, the wi

7 0
3 years ago
How do you find the domain &amp; range for #f(T)=sec(piT/4)#?
allsm [11]
Domain and range of what? im not seeing a set of numbers id be happy to help tho
5 0
3 years ago
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