If this were to be graphed, the independent variable would be the price of the ticket for the rides. The dependent variable would be the total cost.
The fair admission is not a variable because it is a constant price for every single person who goes into the fair.
The problem asks to use y to represent the total cost and x to represent the number of ride tickets. In order to fully write out the equation, we have to figure out what the fair admission costs.
43.75 = 1.25(25) + b
*b represents the fair admission
Multiply 1.25 by 25
43.75 = 31.25 + b
Subtract 31.25 to find what b costs.
12.50 = b
The fair admission costs $12.50.
Solution: y = 1.25x + 12.50
Answer: 0.003757(approx).
Step-by-step explanation:
Total number of combinations of selecting r things out of n things is given by:-
Total cards in a deck = 52
Total number of ways of choosing 8 cards out of 52 = 
Total number of ways to choose 5 clubs and 3 cards with one of each remaining suit = 
[since 1 suit has 13 cards]
The required probability = 
Hence, the required probability is 0.003757 (approx).
The inequality that represents the given graph is y < x/5 -2 OR 5y < x - 10
<h3>Graph of Inequality</h3>
From the question, we are to determine the inequality that represents the graph
First, we will assume the inequality is a straight line and we will determine the equation of the line
From the graph, we have two points on the line
(0, -2) and (5, -1)
Using the formula for the equation of a line with two given point
(y - y₁)/(x -x₁) = (y₂ - y₁)/ (x₂ - x₁)
x₁ = 0
y₁ = -2
x₂ = 5
y₂ = -1
Thus,
(y - -2)/(x - 0) = (-1 - -2)/ (5 - 0)
(y +2)/(x - 0) = (-1 + 2)/ (5 - 0)
(y +2)/(x ) = 1/ 5
5(y + 2) =1(x)
5y + 10 = x
5y = x - 10
y = 1/5(x) - 2
y = x/5 - 2
Now,
Since the solution is below the line and the line is dotted
The inequality becomes
y < x/5 -2
OR
5y < x - 10
Hence, the inequality that represents the given graph is y < x/5 -2 OR 5y < x - 10
Learn more on Graph of Inequality here: brainly.com/question/17106134
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Y intercept = when x = 0
Plug in x = 0
0 + 3y = 6
3y = 6, y = 2
Solution: a, (0,2)
