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PSYCHO15rus [73]
4 years ago
15

Regroup tens as hundreds

Mathematics
1 answer:
Andrew [12]4 years ago
3 0
35 tens

tens = 10 ones = 0.1 hundreds

35 tens = 350 ones = 3.5 hundreds

So 35 tens = 3.5 hundreds
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Identify the perimeter and area of a square with diagonal length 11in. Give your answer in simplest radical form.
ololo11 [35]

Answer: Perimeter = 22*sqrt(2)

Area = 60.5 inches

Step-by-step explanation:

Simple a  square has 4 equal sides.

It contains (by definition) 1 right angle but since we are not including and statement about parallel sides, it needs 4 right angles.

7 0
3 years ago
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Solve the equation x2 + x = 12.
Otrada [13]

please give brainliest

Let's solve your equation step-by-step.

x2+x=12

Step 1: Subtract 12 from both sides.

x2+x−12=12−12

x2+x−12=0

Step 2: Factor left side of equation.

(x−3)(x+4)=0

Step 3: Set factors equal to 0.

x−3=0 or x+4=0

x=3 or x=−4

Answer:

x=3 or x=−4

3 0
2 years ago
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Tom has a recipe for punch that calls for 1/2 gallon of fruit drink, how much fruit drink will tom need to make 5/2 batches of t
Hunter-Best [27]

Answer:

Tom will need \dfrac{5}{4} gallons of fruit drink.

Step-by-step explanation:

Hint- This question can be solved by unitary method.

Tom has a recipe for punch that calls for \dfrac{1}{2} gallon of fruit drink.

i.e for 1 batch of the punch Tom needs \dfrac{1}{2} gallon of fruit drink.

For \dfrac{5}{2} batch of the punch Tom needs \dfrac{1}{2}\times \dfrac{5}{2}=\dfrac{5}{4} gallons of fruit drink.

Therefore, Tom will need \dfrac{5}{4} gallons of fruit drink.

4 0
4 years ago
Rain fell on four days in June. These amounts were recorded: 5 mm, 9 mm, 2 cm, and 2.6 cm. What was the total rainfall for June?
ivolga24 [154]
Hello there

The correct answer in mm would be 60 mm

1 cm = 10 mm

So it would 5+9+20+26 = 60

In cm it would be 6 cm

10 mm = 1 cm

.5+.9+2+2.6 = 6

I hope this helped ^^
8 0
3 years ago
FASTEST WITH EXPLAINATION ANSWER GETS BRAINLIEST
castortr0y [4]

Answer:

explanation to what

Step-by-step explanation:

6 0
3 years ago
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