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PSYCHO15rus [73]
3 years ago
15

Regroup tens as hundreds

Mathematics
1 answer:
Andrew [12]3 years ago
3 0
35 tens

tens = 10 ones = 0.1 hundreds

35 tens = 350 ones = 3.5 hundreds

So 35 tens = 3.5 hundreds
You might be interested in
What is the missing length?
TEA [102]
Answer:  13.722 km ;  or, write as:  13  13/18 km .
___________________________________________________
Explanation:
___________________________________________________
Area = Length * width ; 
___________________________________________________
or, write as:  A = L * w ;
________________________

Given: A = 247 km² ; 
           
          L = 18 km ; 
 
          w = "y" ; 
________________________
 Find:  "y"
______________________________
  A = L * w ; 
______________________________
Plug in our values:
______________________________
  247 km² = 18 km * "y" ;  solve for "y" (in units of "km") ;

_____________________________
        18 y = 247 ; 
___________________________________________________________
Divide each side of the equation by "18"; to isolate "y" on one side of the equation; and to solve for "y" :
___________________________________________________________
        18 y / 18 = 247 / 18 ;
_____________________________________________
  to get:
_____________________________________________
              y = 13.7222222222222222...... km ;  round to: 13.722 km

                   or;  y = 13  13/18 km .
_______________________________________________
3 0
3 years ago
Simplify (9x^3-4x+10)+(x^3+10x-9)
Alex

Simplify

9x^3 - 4x + 10 + x^3 + 10x - 9

Collect like terms

(9x^3 + x^3) + (-4x + 10x) + (10 - 9)

Simplify

<u>10x^2 + 6x + 1</u>

6 0
3 years ago
What is the explicit formula for the following sequence: -4, -1, 2, 5...?
stiv31 [10]
U have an arithmetic sequence with a common difference of 3

A(n) = -4 + (n-1) * 3
4 0
3 years ago
Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s
Nataliya [291]

Answer:

f(x)=\frac{1}{2}x^2-4x+5

Step-by-step explanation:

A parabola is written in the form

f(x)=a((x-h)^2+k) (1)

where:

h is the x-coordinate of the vertex of the parabola

ak is the y-coordinate of the vertex of the parabola

a is a scale factor

For the parabola in the problem, we know that the vertex has  coordinates (4,-3), so we have:

h=4 (2)

ak=-3

From this last equation, we get that a=\frac{-3}{k} (3)

Substituting (2) and (3) into (1) we get the new expression:

f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3 (4)

We also know that the parabola  contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6

So we also get:

a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}

So the equation of the parabola is:

f(x)=\frac{1}{2}((x-4)^2 -6) (5)

Now we want to rewrite it in the standard form, i.e. in the form

f(x)=ax^2+bx+c

To do that, we simply rewrite (5) expliciting the various terms, we find:

f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5

6 0
3 years ago
What is the most precise classification of the quadrilateral?
Naddik [55]
It's F because a quadrilateral is at those classifications
4 0
3 years ago
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