Answer:
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Step-by-step explanation:
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Hirap math nanaman
The simplified expression of (x^0 y^2/3 z^-2y^)^2/3 divided by (x^2 z^1/2)^-6 is x^(12) y^(10/9) z^(-1/3)
<h3>How to simplify the expression?</h3>
The algebraic statement is given as:
(x^0 y^2/3 z^-2y^)^2/3 divided by (x^2 z^1/2)^-6
Rewrite the algebraic statement as:
[(x^0 y^2/3 z^-2y)^2/3]/[(x^2 z^1/2)^-6]
Evaluate the like factors
[(x^0 y^(2/3+1) z^-2)^2/3]/[(x^2 z^1/2)^-6]
Evaluate the sum
[(x^0 y^5/3 z^-2)^2/3]/[(x^2 z^1/2)^-6]
Expand the exponents
[(x^(0*2/3) y^(5/3 * 2/3)z^(-2*2/3)]/[(x^(2*-6) z^(1/2*-6)]
Evaluate the products
[(x^0 y^(10/9) z^(-4/3)]/[(x^(-12) z^(-3)]
Apply the quotient law of indices
x^(0+12) y^(10/9) z^(-4/3+3)
Evaluate the sum of exponents
x^(12) y^(10/9) z^(-1/3)
Hence, the simplified expression of (x^0 y^2/3 z^-2y^)^2/3 divided by (x^2 z^1/2)^-6 is x^(12) y^(10/9) z^(-1/3)
Read more about simplified expression at:
brainly.com/question/723406
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Let ordered pairs
X Y
-1 1
-2 2
-3 3
-4 4
-5 5
<span> What kind of figure do you get?
For this case a straight line was obtained, whose equation is
</span><span> y = -x
</span><span> In what quadrants does the figure lie?
The figure is in the second quadrant. (See graphic)
</span>
