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slamgirl [31]
3 years ago
8

Write 0.0155 as a fraction in simplest form

Mathematics
1 answer:
ser-zykov [4K]3 years ago
5 0
155/10,000 divided by 5

31/2000 =0.0155
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Cedric orders at least 30 bottles of styling gel per month for his hair care business. The supplier charges $3 per pint bottle p
Rama09 [41]
He buys 30 bottles which each costs 3 dollars. So 30 times 3 means he pays 90 dollars. Plus the 25 dollar handling fee which is 115. However the competing supplier is 4 dollars every bottle for the pint bottle. So if he bought 30 times 4 he would pay 120. That is without the handling money. So thats why he should stay with his

5 0
3 years ago
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150% of 66(Need the work shown)
ANTONII [103]
66 is the 100%
we can solve this problem by the rule of three.

Therefore:
66------------------------100%
x--------------------------150%

x=(66 * 150%) / 100%=99

Answer 150% of 66 is 99.

Other method:
150% of 66=1.5 *66=99

Answer: 150% of 66 is 99.
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3 years ago
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The formula for the volume of a cone is V=1/3 pi r2h the radius r of the cone may be expressed as
Naily [24]

r = √(3V/πh)

multiply both sides by 3 to eliminate the fraction

πr²h = 3V ( divide both sides by πh )

r² = 3V/ πh ( take the square root of both sides )

r = √(3V/πh)


3 0
2 years ago
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A store has been selling 300 Blu-ray disc players a week at $600 each. A market survey indicates that for each $40 rebate offere
timurjin [86]

Answer:

75 $

Step-by-step explanation:

According to problem statement p(300) = 600

And we know that with a rebate of 40 $, numbers of units sold will increase by 80 then if x is number of units sold, the increase in units is

(  x  - 300 )  , and the price decrease

(1/80)*40  =  0,5

Then the demand function is:

D(x)  =  600  - 0,5* ( x - 300 )  (1)

And revenue function is:

R(x) =  x * (D(x)   ⇒   R(x) =  x* [  600  - 0,5* ( x - 300 )]

R(x) = 600*x  - 0,5*x * ( x - 300 )

R(x) = 600*x - 0,5*x² - 150*x

R(x) = 450*x  - (1/2)*x²

Now taking derivatives on both sides of the equation we get

R´(x) =  450  - x

R´(x) =  0       ⇒   450  - x = 0

x = 450 units

We can observe that for   0 < x  < 450  R(x) > 0 then R(x) has a maximum for x = 450

Plugging this value in demand equation, we get the rebate for maximize revenue

D(450)  =  600  - 0,5* ( x - 300 )

D(450)  =  600 - 225 + 150

D(450)  =

D(450)  =  600 - 0,5*( 150)

D(450)  =  600 - 75

D(450)  = 525

And the rebate must be

600 - 525  = 75 $

5 0
3 years ago
Please help
Mice21 [21]

Answer:

Option A:

y = 3*(x - 5)^2 - 4

Step-by-step explanation:

For a quadratic equation:

y = a*x^2 + b*x + c

with the vertex (h, k), we can rewrite the function as:

such that:

h = -b/2*a

y = a*(x - h)^2 + k

Here we have the function:

y = 3*x^2 - 30*x + 71

the x-value of the vertex will be:

h = -(-30)/(2*3) = 30/6 = 5

And k is given by:

k = y(5) = 3*(5)^2 - 30*5 + 71 = -4

Then the vertex is:

(5, - 4)

And we can rewrite the equation in the vertex form as:

y = 3*(x - 5)^2 + (-4)

y = 3*(x - 5)^2 - 4

Then the correct option is A.

7 0
3 years ago
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