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creativ13 [48]
4 years ago
10

The graph below plots a function f(x):

Mathematics
1 answer:
Karolina [17]4 years ago
4 0
By definition we have that the average rate of change of the function is given by:
 AVR =  \frac{f(x2) - f(x1)}{x2 - x1}

 Substituting values we have:
 AVR = \frac{100 - 50}{2 - 0}
 Rewriting we have:
 AVR = \frac{50}{2}
 AVR = 25
 Answer:
 If x represents time, the average rate of change of the function f(x) in the first two seconds is 25.
You might be interested in
Write an equation in slope-intercept form for the line perpendicular to y = -4x + 2 that passes through the point (–5, 2).​
cricket20 [7]

Answer:

y = 5 /2 x − 2

Step-by-step explanation:

The slope-intercept form of a linear equation is:  y = m x + b   Where  m  is the slope and  b  is the y-intercept value.

6 0
3 years ago
If the value of third order determinant is 11. Then what is the value of the determinant formed by its cofactors.
nordsb [41]

Answer:

146.41

Step-by-step explanation:

third order determinant = determinant of 3×3 matrix A

given ∣A∣=11

det (cofactor matrix of A) =set (transpare of cofactor amtrix of A) (transpare does not change the det)

=det(adjacent of A)

{det (cofactor matrix of A)}  ^2  = {det (adjacent of A)} ^2

 

(Using for an n×n det (cofactor matrix of A)=det (A)^n−1 )

we get

det (cofactor matrix of A)^2  = {det(A)  ^3−1 }^2

 

=(11)^2×2  = 11^4

 =146.41

5 0
3 years ago
Wich expression can be used to find the slope of a line containing the points (-3,2) and (7,-1)
docker41 [41]
A(x_1;\ y_1);\ B(x_2;\ y_2)\\\\\text{The slope:}\ m=\dfrac{y_2-y_1}{x_2-x_1}


\text{We have:}\\(-3;\ 2)\to\ x_1=-3;\ y_1=2\\(7;\ -1)\to x_2=7;\ y_2=-1

\text{substitute}\\\\m=\dfrac{-1-2}{7-(-3)}=\dfrac{-3}{10}=-\dfrac{3}{10}
6 0
3 years ago
Solve each equation write each equation in simplest form 7x/8=21
AveGali [126]
7x / 8 = 21
7x = 8*21
x = 24
8 0
3 years ago
Consider the quadratic function: y = 2x^2 + 7x + 10
arsen [322]

Answer:

y-intercept: 10

concavity: function opens up

min/max: min

Step-by-step explanation:

1.) The definition of a y-intercept is what the resulting value of a function is when x is equal to 0.

Therefore, if the function's equation is given, to find y-intercept simply plug in 0 for the x-values:

y = 2x^2+7x+10 = 2(0)^2 + 7(0)+10 = 2(0) + 0 + 10 = 0 + 10 = 10

y intercept ( f(0) )= 10

2.) In order to find concavity (whether a function opens up or down) of a quadratic function, you can simply find the sign associated with the x^2 value. Since 2x^2 is positive, the concavity is positive. This is basically possible, since it is identifying any reflections affecting the y-values / horizontal reflections.

3.) In order to find whether a quadratic function has a maximum or minimum, you can use the concavity of the function. The idea is that if the function opens downwards, the vertex would be at the very top, resulting in a maximum. If a function was open upwards, the vertex would be at the very bottom, meaning there is a minimum. Like the concavity, if the value associated with x^2 is positive, there is a minimum. If it is negative, there is a maximum. Since 2x^2 is positive, the function has a minimum.

7 0
2 years ago
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