<h2>
Answer:</h2><h2>The theoretical probability of four students from your school being selected as contestants out of 8 possible contestants spots =

</h2>
Step-by-step explanation:
The number of students participated = 30
Total audience = 150
By probability , to find the solution =
where n(E) is the number of favorable outcomes,
n(S) is the number of total outcomes.
n(S) is the number of ways any 8 students can by picked from the audience= 
n(E) is the probability of picking four students from our school and five students from another school.
n(E) =
= 
=
= 
Answer:
sorry i dont know what the answer is
Step-by-step explanation:
Answer:
0
Step-by-step explanation:
We find the determinant of a matrix by the method below. If we have a matrix:
![\left[\begin{array}{cc}a&b\\c&d\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D)
The determinant is 
Now, using cramer's rule, we find x-value by the formula:

Where D is the determinant of the original problem and
is the determinant of the x-value matrix. How do we get those?
<u><em>To get original matrix and thus D, we set up the matrix as the coefficients of x and y (s) of both the equations and to get matrix of x-value and thus
, we replace the x values of the matrix with the numbers in the right hand side of the 2 equations.</em></u> We show this below:
<em />
<em>To get D:</em>
![\left[\begin{array}{cc}3&4\\1&-6\end{array}\right] \\D=(3)(-6)-(1)(4)=-18-4=-22](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%264%5C%5C1%26-6%5Cend%7Barray%7D%5Cright%5D%20%5C%5CD%3D%283%29%28-6%29-%281%29%284%29%3D-18-4%3D-22)
<em>To get
:</em>
<em>
</em>
<em />
<em>Putting into the formula, we get:</em>
<em>
</em>
<em />
<em>Thus, the value of x is 0</em>
Percent change=change/original times 100
change=75 to 25 or 75-25=50
so
percent change=50/75 times 100=0.6666666 times 100=66.66666%
tenth
66.7%
I think 35/70 is the answer