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3 years ago

2ln(5x)=8 solve for x

2 answers:

8 0

$lnx=log_ex\\----------\\log_ab=c\iff a^c=b\\----------\\Domain:\\5x > 0\ \ \ |divide\ both\ sides\ by\ 5\\x > 0\\D:x\in\mathbb{R^+}\\----------------------\\2ln(5x)=8\ \ \ \ |divide\ both\ sides\ by\ 2\\\\ln(5x)=4\iff e^4=5x\\\\5x=e^4\ \ \ \ \ |divide\ both\ sides\ by\ 5\\\\\boxed{x=\frac{e^4}{5}\in D}$

Yakvenalex [24]3 years ago

5 0

2ln(5x)=8

ln(5x) = 4

e^4 = 5x

x = (e^4) / 5

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Which ordered pairs are solution of the inequality?

Anarel [89]

Answer:

The answer would be A, D, and C.

Step-by-step explanation:

y=1, so

1 > 2(1) -2

1> 2-2

1>0 TRUE

NEXT.

y=3

3> 2(-1) -2

3>-2-2

3> -4 TRUE

y=-2

4>2(2) -2

4 > 4-2

4>2 TRUE!

I hope this helps!

8 0

3 years ago

A.Vertical B.Adjacent C.complementary D.Supplementary E.none

Alexxx [7]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

An art history professor assigns letter grades on a test according to the following scheme. A: Top 13% of scores B: Scores below

madam [21]

Answer:

The numerical limits for a B grade are 81 and 89, that is, a score between 81 and 89 gets a B grade.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Scores on the test are normally distributed with a mean of 79.7 and a standard deviation of 8.4.

This means that $\mu = 79.7, \sigma = 8.4$

B: Scores below the top 13% and above the bottom 56%

So between the 56th percentile and the 100 - 13 = 87th percentile.

56th percentile:

X when Z has a p-value of 0.56, so X when Z = 0.15. Then

$Z = \frac{X - \mu}{\sigma}$

$0.15 = \frac{X - 79.7}{8.4}$

$X - 79.7 = 0.15*8.4$

$X = 81$

87th percentile:

X when Z has a p-value of 0.87, so X when Z = 1.13.

$Z = \frac{X - \mu}{\sigma}$

$1.13 = \frac{X - 79.7}{8.4}$

$X - 79.7 = 1.13*8.4$

$X = 89$

The numerical limits for a B grade are 81 and 89, that is, a score between 81 and 89 gets a B grade.

4 0

2 years ago

A fitness club has two options, one for members and one for nonmembers. Members pay a one-time registration fee of $12 plus $8 p

Liula [17]

Answer:

See below.

Step-by-step explanation:

Let's look at the cost for members (C1) first. Let x be the number of visits.

C1(x) = 12 + 8x

For non-members (C2), we can do the same.

C2(x) = 10x

You can graph these two equations.

x C1 C2

0 12 0

1 20 10

2 28 20

3 36 30

4 44 40

5 52 50

6 60 60

7 68 70

Let's make the two equations equal, to find out where the benefit is the same.

12 + 8x = 10x

2x = 12

x = 6

Up to 5 visits, the non-member cost is better. At 6 visits, there's the same price. For more than 6 visits, the member cost is better.

7 0

3 years ago

Help me please help me please

Nikolay [14]

Answer:

1 second

Step-by-step explanation:

$s=-5\\u=0\\v=\\a=-10\\t=t$

$\begin{aligned}\textsf{Using} \quad s & =ut+\dfrac12at^2\\ \implies -5 & =(0)t+\dfrac12(-10)t^2\\ -5 & = -5t^2\\ t^2& = 1\\ t & = \pm\sqrt{1}\\ t & = 1\: \sf s\end{aligned}$

7 0

2 years ago