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murzikaleks [220]
3 years ago
12

Pls help I will mark brainlist if correct!! :)

Mathematics
1 answer:
Bezzdna [24]3 years ago
8 0

Answer:

B.

Step-by-step explanation:

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What is a synthetic material made of?
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Synthetic fibers are made from raw materials such as petroleum, based on chemicals or petrochemicals [20]. These materials are polymerized into a long, linear chemical with different chemical compounds and are used to produce various types of fibers.

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There were 756 students enrolled in a freshman-level chemistry class. By the end of the semester, the number of students who pas
Alexandra [31]

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4536

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3 years ago
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FREE BRAINLIEST!: (n+2) to the power of 2 - 5a + 1 when n=6 and a=2
BlackZzzverrR [31]

Answer:

55

Step-by-step explanation:

2−5+1+8

11−5

i add 8 because  n is 6 so add 2 it is 8 so i put it in the problem  and got 55

have a nice day and sorry if wrong T_T

6 0
3 years ago
WHICH IS THE CORRECT ANSWER ?!
alex41 [277]

Answer:

B

Step-by-step explanation:

when you calculate in calculator putting all given values it will give 17/8

hope you liked it

8 0
3 years ago
Suppose a certain type of fertilizer has an expected yield per acre of mu 1 with variance sigma 2, whereas the expected yield fo
mart [117]

Answer:

See the proof below.

Step-by-step explanation:

For this case we just need to apply properties of expected value. We know that the estimator is given by:

S^2_p= \frac{(n_1 -1) S^2_1 +(n_2 -1) S^2_2}{n_1 +n_2 -2}

And we want to proof that E(S^2_p)= \sigma^2

So we can begin with this:

E(S^2_p)= E(\frac{(n_1 -1) S^2_1 +(n_2 -1) S^2_2}{n_1 +n_2 -2})

And we can distribute the expected value into the temrs like this:

E(S^2_p)= \frac{(n_1 -1) E(S^2_1) +(n_2 -1) E(S^2_2)}{n_1 +n_2 -2}

And we know that the expected value for the estimator of the variance s is \sigma, or in other way E(s) = \sigma so if we apply this property here we have:

E(S^2_p)= \frac{(n_1 -1 )\sigma^2_1 +(n_2 -1) \sigma^2_2}{n_1 +n_2 -2}

And we know that \sigma^2_1 = \sigma^2_2 = \sigma^2 so using this we can take common factor like this:

E(S^2_p)= \frac{(n_1 -1) +(n_2 -1)}{n_1 +n_2 -2} \sigma^2 =\sigma^2

And then we see that the pooled variance is an unbiased estimator for the population variance when we have two population with the same variance.

8 0
3 years ago
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