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Mariulka [41]
2 years ago
6

Sorry really bad with fractions!! Help

Mathematics
2 answers:
earnstyle [38]2 years ago
3 0
X/4 + 1 = -6 
x/4 = -6 -1 
x/4 = -7 
x= -28 
nalin [4]2 years ago
3 0
\frac{x}{4} + 1 = -6
(\frac{x}{4} + 1) X 4 = -6 X 4
x + 4 = -24
(x + 4) - 4 = -24 - 4
x = -28
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michael has a very large soup pot shape like a cylinder that has height of 15 inches and a radius of 6 inches
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Find an equation for the line with the given properties. Perpendicular to the line x - 6y = 8; containing the point (4,4) O 1) y
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Answer:

Option 3 - y=-6x+28

Step-by-step explanation:

Given : Perpendicular to the line x - 6y = 8; containing the point (4,4).

To Find : An equation for the line with the given properties ?

Solution :

We know that,

When two lines are perpendicular then slope of one equation is negative reciprocal of another equation.

Slope of the equation x - 6y = 8

Converting into slope form y=mx+c,

Where m is the slope.

y=\frac{x-8}{6}

y=\frac{x}{6}-\frac{8}{6}

The slope of the equation is m=\frac{1}{6}

The slope of the perpendicular equation is m_1=-\frac{1}{m}

The required slope is m_1=-\frac{1}{\frac{1}{6}}

m_1=-6

The required equation is y=-6x+c

Substitute point (x,y)=(4,4)

4=-6(4)+c

4=-24+c

c=28

Substitute back in equation,

y=-6x+28

Therefore, The required equation for the line is y=-6x+28

So, Option 3 is correct.

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