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Pavel [41]
3 years ago
11

HELPPPPPP MEEEEEEEEEEEEEEE

Mathematics
1 answer:
sertanlavr [38]3 years ago
7 0
5 to be honest I just guess
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Morgarella [4.7K]
You get an answer to your question really quick,
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3 0
3 years ago
Read 2 more answers
A point is randomly chosen in the circle shown below.
quester [9]

Answer:

in a region with a letter

Step-by-step explanation:

For a certainty, then probability is 1.

That means sum of probability of all events in the sample space.

This means P(A)+P(B)+P(C)+P(D)=1

This is equivalent to:

P(A or B or C or D)=1

Hence for certainty, the region must be:

A or B or C or D

So the correct answer is in a region with a letter.

7 0
3 years ago
Sasha sells T-shirts. Each day she earns a set amount, plus a commission.
WARRIOR [948]

Answer:

Domain → 0 < x < 5

Step-by-step explanation:

Sasha sells T-shirts and earns a fixed amount plus a commission by selling each shirt. (As given in the table)

Table attached shows a linear function (A regular increase in total pay with the increase in number of shirts sold)

So the input values of the table (Number of shirts sold) will represent the domain of the linear function.

Hence, reasonable domain for the function will be → 0 < x < 5

5 0
3 years ago
What is 0.95 rounded off to the nearest whole number
mihalych1998 [28]

1.00 would be your answer because 95 rounded up is 100. So, 0.95 is closest to 1.00

8 0
3 years ago
What are the possible rational roots of the polynomial equation?<br><br> 0=2x7+3x5−9x2+6
RoseWind [281]

Answer: \pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0

Where:

- The coefficients are integers.

- a_n is the leading coeffcient (a_n\neq 0)

- a_0 is the constant term a_0\neq 0

Every rational root of the polynomial is in the form:

\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}

For the case of the given polynomial:

2x^7+3x^5-9x^2+6=0

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

 Then, by Rational Roots Test we get the possible rational roots of this polynomial:

\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

5 0
2 years ago
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