Answer:
1. 64cm² , 2. 240yd² , 3.≈220.5cm² , 4.≈193.4m² , 5. 38.6ft² , 6. ≈78.1yd² , 7. ≈120.7
Step-by-step explanation:
1. A=12x4.5+2x5 , 2. A=24x8+0.5x12x8 3. A=0.5x16x15+0.5x8²π ,4. A=7x15+0.5(15/2)² 12 ,5. A=3.6(16/2)+0.5x7x2.8 ,6. A=8(16/2)+0.5x9π ,7. A=(8/4)x5²xcot(180/8)
Answer:
1
Step-by-step explanation:
slope (k) is the rise over run of the line
a way of finding the slope if you have two dots of the line is:
here the dots that belong to the line that you can most easily see are:
A(-6,0)
B(0,6)
by inserting the values into the euquation you get:
good luck with your maths solving
Answer:
f(x) = -3x + 10
Step-by-step explanation:
Substitute values to find b;
y=mx+b
y=-3x+b
<em>Replace X and Y</em>
4=-3(2)+b
4=-6+b
<em>Swap sides to set equal to b. Swapping causes sign change</em>
4+6=b
10=b
Answer:
Step-by-step explanation:
The coefficient of determination = 
= 0.7832
It means about 78% variation in waist size of males can be explained by their weight and about 23% can not be explained.
Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
