It all depends on the math question but usually you solve for x, then check it. Plug x back in and see if it works. But it all depends on the math problem
X^3 = 216
by taking cubic root for both sides
![\sqrt[3]{x^3} = \sqrt[3]{216}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E3%7D%20%3D%20%20%5Csqrt%5B3%5D%7B216%7D%20)
x = 6
Answer:
Probability at least one car will get punctured: 0.39347
Step-by-step explanation:
B(10,000 , 0.00005)
P(X ≥ 1) = 1 - P(X = 0)
= 1 - (1 - 0.00005)^10,000
= 1 - (0.99995)^10,000
= 1 - 0.60652...
= 0.39347 (probability that at least one car will get punctured)
As you can tell P(X ≥ 1) as we have to solve for the probability that at least one car will get punctured. That is of course 1 - [ P(X = 0) ].
Answer:
? = 57
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
cos ? = adj/ hyp
cos ? = 14/26
Taking the inverse cos of each side
cos ^-1 ( cos ?) = cos ^-1 ( 14/26)
? = 57.42102961
To the nearest degree
? = 57
