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Marianna [84]
3 years ago
11

Tim picked up 20% of the books in the room. If he picked up 8 books, how many were in the room? Explain your answer please, I wi

ll mark it brainly! :)
Mathematics
2 answers:
fenix001 [56]3 years ago
6 0

Answer: 40 books

Step-by-step explanation: 20%=8 Books

100 divided by 20 = 5

8 x 5 = 40

Mrac [35]3 years ago
6 0
Divide 20% by 100 to obtain its decimal form. Dividing 20% by 100 equals 0.2. Set up an equation as 0.2x = 8 which means 20% of x equals 8. Solve the equation by dividing each side by 0.2, Dividing 0.2 from each side results in x=40 Eight is 20% of 40
So there were 40 books in the room and he took 8 making the books 20% less.
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Plz help me get the right answer ASAP please
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(7x * x) + (7x * 20)

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7x^{2} + 140x


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3 years ago
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sergiy2304 [10]
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3 years ago
kyle has 105 baseball cards and must give 2/5 of his cards away. how many cards will kyle give away? what fraction of his cards
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3 years ago
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The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E
nexus9112 [7]

Answer:

The projected enrollment is \lim_{t \to \infty} E(t)=10,000

Step-by-step explanation:

Consider the provided projected rate.

E'(t) = 12000(t + 9)^{\frac{-3}{2}}

Integrate the above function.

E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt

E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c

2000=-\frac{24000}{3}+c

2000=-8000+c

c=10,000

Therefore, E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

Now we need to find \lim_{t \to \infty} E(t)

\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

\lim_{t \to \infty} E(t)=10,000

Hence, the projected enrollment is \lim_{t \to \infty} E(t)=10,000

8 0
2 years ago
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