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2 years ago

N +-6 = 11 Please answer!

Mathematics

2 answers:

anastassius [24]2 years ago

3 0

Answer:

n = 17

Step-by-step explanation:

+(-6) is the same thing as n - 6 = 11 to take out the + sign in order to avoid confusion. Add 6 on both sides to get your n value which is 17.

konstantin123 [22]2 years ago

3 0

Answer:

Step-by-step explanation:

here you go mate

step 1

n +-6 = 11 equation/Question

step 2

n +-6 = 11 add 6 to each side

n-6(+6)=11(+6)

answer

n=17

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If 60% of people said that they like

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Answer:

40%

Step-by-step explanation:

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3 years ago

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Please help me <br> Show your work <br> 10 points

Svet_ta [14]

<h2>Answer</h2>

After the dilation $\frac{5}{3}$ around the center of dilation (2, -2), our triangle will have coordinates:

$R'=(2,3)$

$S'=(2,-2)$

$T'=(-3,-2)$

<h2>Explanation</h2>

First, we are going to translate the center of dilation to the origin. Since the center of dilation is (2, -2) we need to move two units to the left (-2) and two units up (2) to get to the origin. Therefore, our first partial rule will be:

$(x,y)$ → $(x-2, y+2)$

Next, we are going to perform our dilation, so we are going to multiply our resulting point by the dilation factor $\frac{5}{3}$ . Therefore our second partial rule will be:

$(x,y)$ → $\frac{5}{3} (x-2,y+2)$

$(x,y)$ → $(\frac{5}{3} x-\frac{10}{3} ,\frac{5}{3} y+\frac{10}{3} )$

Now, the only thing left to create our actual rule is going back from the origin to the original center of dilation, so we need to move two units to the right (2) and two units down (-2)

$(x,y)$ → $(\frac{5}{3} x-\frac{10}{3}+2,\frac{5}{3} y+\frac{10}{3}-2)$

$(x,y)$ → $(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})$

Now that we have our rule, we just need to apply it to each point of our triangle to perform the required dilation:

$R=(2,1)$

$R'=(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})$

$R'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(1)+ \frac{4}{3})$

$R'=(\frac{10}{3} -\frac{4}{3} ,\frac{5}{3}+ \frac{4}{3})$

$R'=(2,3)$

$S=(2,-2)$

$S'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})$

$S'=(\frac{10}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})$

$S'=(2,-2)$

$T=(-1,-2)$

$T'=(\frac{5}{3} (-1)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})$

$T'=(-\frac{5}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})$

$T'=(-3,-2)$

Now we can finally draw our triangle:

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2 years ago

The City Housing Authority has received 50 applications from qualified applicants for eight low-income apartments. Three of the

OlgaM077 [116]

The probability that both specific qualified applicants will be among the eight selected is given by:
$P(2\ specified)=\frac{2C2\times 48C6}{50C8}=0.0229$
The probability that the two will get apartments on the North side is given by:
$P(North)=\frac{3C2\times5C0}{8C2}=0.107$
The probability that the two will get apartments on the South side is given by:
$P(South)=\frac{5C2\times3C0}{8C2}=0.357$
The events '2 apartments on North side' and '2 apartments on South side' are mutually exclusive. Therefore the probability the two specific qualified applicants will be on the same side of town is 0.107 + 0.357 = 0.464.
Finally, the probability that two specific qualified applicants will be selected for apartments on the same side of town is found from:
$0.0229\times0.464=0.01063$

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2 years ago

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Answer:

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