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ohaa [14]
2 years ago
13

Which data would most likely show a negative relationship when graphed on a scatterplot?

Mathematics
1 answer:
IRINA_888 [86]2 years ago
5 0
The correct answer is C . Outside temperature
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1.Selena is studying about a square with side x, and a rectangle whose length is
kondaur [170]

Answers:

1.  No I don't agree with Selena because the area of the rectangle has the exact same area of the square

Step-by-step explanation:

1.     square = x

rectangle length = 6 + x

rectangle width = x - 6

the plus 6 and minus 6 cancel each other out and make the same area that the square has.

Im sorry i dont know what the answe to 2 is.

3 0
2 years ago
What the answer is for the question
Slav-nsk [51]
The answer would be -144
7 0
2 years ago
In a right triangle ABC,angleB=90°<br>(a) If AB=6cm,BC=8cm find AC<br>(b) if AC=13cm,BC=5cm find AB​
CaHeK987 [17]

Step-by-step explanation:

hypotenuse =

\sqrt{a {}^{2} + b {}^{2}  }

3 0
2 years ago
I need the answers for this question. I am confused
noname [10]

Answer:

Step-by-step explanation:

As C and D are both at y = -9, the line below V₂ is vertical and located at

x = ½(22 + (-2) = 10

The line between V₁ and V₂ will contain the point halfway between B and D.

x = ½(14 + (-2)) = 6

y = ½(7 + (-9)) = -1

(6, -1)

The slope of the line between V₁ and V₂ is the same as between V₁ and our just found midpoint between B and D

m = (5 - (-1)) / (0 - 6) = -1

so the line equation is

y = -x + 5

Which intersects x = 10 at

y = -10 + 5 = -5

V₂ = (10, -5)

The distance between V₂ and B, C, and D is

d = √((14 - 10)² + (7 - (-5))²) = √160

The distance between V₁ and B, A, and D is

d = √((-10 - 0)² + (15 - 5)²) = √200

As √200 > √160, the dump should be located at V₁ or at least √200 away from any two of the points

5 0
3 years ago
1+-2/3--m where m=9/2
statuscvo [17]

Answer:

-25/9

Step-by-step explanation:

1 + (-2/3) - m

Plug in:

1 + (-2/3) - 9/2

1 + 2/3 - 9/2

1/3 - 9/2

-25/9

Hope this helped.

5 0
3 years ago
Read 2 more answers
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