A, C and E all work in the equations. In order for them to work, you must use the ordered pair in each of the three situations. Below is the work for all of the correct answers.
Ordered Pair A : (1, -1)
y < x + 1
-1 < 1 + 1
-1 < 1 (TRUE)
y < 4
-1 < 4 (TRUE)
x < 6
1 < 6 (TRUE)
Ordered Pair C : (4, 2)
y < x + 1
2 < 4 + 1
2 < 5 (TRUE)
y < 4
2 < 4 (TRUE)
x < 6
5 < 6 (TRUE)
Ordered Pair E : (4, -2)
y < x + 1
-2 < 4 + 1
-2 < 5 (TRUE)
y < 4
-2 < 4 (TRUE)
x < 6
4 < 6 (TRUE)
Answer:
(4, 1)
Step-by-step explanation:
x^2 + y^2 - 2y - 8x - 19 = 0
We rearrange the terms and complete the square twice.
x^2 - 8x + y^2 - 2y = 19
x^2 - 8x + 16 + y^2 - 2y + 1 = 19 + 16 + 1
(x - 4)^2 + (y - 1)^2 = 6^2
The center is (4, 1)
Answer:
Option 1 - y cubed z superscript 4
Step-by-step explanation:
Given : Expression y times y times y times z times z times z times z.
To find : Which expression is equivalent to given expression ?
Solution :
Re-write the expression as,
Write the number of time value repeat itself as the power,
or we can say that the expression is y cubed z superscript 4.
Therefore, option 1 is correct.
Answer: 2: a 3: b 4:b
Step-by-step explanation:
Answer:
x^2 + 5x - 84 = 0
x = 7
Step-by-step explanation:
let the sister's age = y
sister's age (y) = 5 + x equation 1
xy = 84 equation 2
Make y the subject of the formula in equation 2
y = 84/x
equate equation 1 and 2
84/x = 5 + x equation 3
Multiply equation 3 by x
84 = 5x + x^2
x^2 + 5x - 84 = 0
tjis can be solved using quadratic equation
x^2 -7x + 12x -84 = 0
x(x + 12) -7(x + 12)
x = 7 or - 12
age cant be negative so his age is 7
