Area of the shaded region square cm
Perimeter of the shaded region cm
Solution:
Radius of the quarter of circle = 12 cm
Area of the shaded region = Area of quarter of circle – Area of the triangle
square cm.
Area of the shaded region square cm
Using Pythagoras theorem,
Taking square root on both sides of the equation, we get
cm
Perimeter of the quadrant of a circle =
cm
Perimeter of the shaded region = cm
cm
Hence area of the shaded region square cm
Perimeter of the shaded region cm
Answer:
x = 6
Step-by-step explanation:
let 'x' = BD
x/3 = 12/x
x² = 36
x =
x = 6
Answer:
3*sqrt(3x)
--------------
2x
Step-by-step explanation:
To rationalize the denominator, we need to get rid of the square root. We need to multiply by sqrt(12x)/sqrt(12x)
9 sqrt(12x)
---------- * -----------
sqrt(12x) sqrt(12x)
9sqrt(12x)
-----------------
12x
We can cancel 3 in the top and bottom
3sqrt(12x)
---------------
4x
We also notice that 12 is made up of 4 and 3
3sqrt(4) sqrt(3x)
---------------
4x
3sqrt(4) sqrt(3x)
----------------------
4x
3*2sqrt(3x)
--------------
4x
We can cancel a 2 in the top and bottom
3*sqrt(3x)
--------------
2x
Centi = Hundreds.
1.5533.
Round up by seeing if the number to the right of the hundreds place is 5 or higher. If it's not, don't change anything.
1.55 is your answer.