All categories

3 years ago

the total of three cousins' ages 48. sam is half as old as jack and 4 years older than max. how old are the cousins

Mathematics

1 answer:

weeeeeb [17]3 years ago

7 0

HEY THERE.

I THINK THE CORRECT ANSWER IS...SAM IS 20

You might be interested in

Describe the relationship between the area of a parallelogram and the area of a triangle if they have the same base and the same

KengaRu [80]

Answer:

the area of the triangle is half the area of parallelogram

Step-by-step explanation:

8 0

2 years ago

Y=3x+8 what is the answer for this slope

sp2606 [1]

3 because y=mx+c and m=slope

4 0

3 years ago

Yesterday, Joe had $376 in his bank account. Today, Joe noticed his account had a balance of -$523. Joe realized that he spent m

Phantasy [73]

Joe overspent D. $899

7 0

3 years ago

Directions : Factor each of the following Differences of two squares and write your answer together with solution

N76 [4]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Factor each of the following differences of two squares and write your answer together with solution.

$\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}$

$\sf \: x ^ { 2 } - 36$

Rewrite $\sf\:x^{2}-36 as x^{2}-6^{2}$ . The difference of squares can be factored using the rule: $\sf\: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$ .

$\boxed{ \boxed{ \bf\left(x-6\right)\left(x+6\right) }}$

__________________

$\sf \: 49 - x ^ { 2 }$

Rewrite 49-x² as 7²-x². The difference of squares can be factored using the rule: $\sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$ .

$\sf \: \left(7-x\right)\left(7+x\right)$

Reorder the terms.

$\boxed{ \boxed{ \bf\left(-x+7\right)\left(x+7\right) }}$

__________________

$\sf \: 81 - c ^ { 2 }$

Rewrite 81-c²as 9²-c². The difference of squares can be factored using the rule: $\sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$ .

$\sf\left(9-c\right)\left(9+c\right)$

Reorder the terms.

$\boxed{ \boxed{ \bf\left(-c+9\right)\left(c+9\right) }}$

__________________

$\sf \: m ^ { 2 } n ^ { 2 } - 1$

Rewrite m²n² - 1 as $\sf\left(mn\right)^{2}-1^{2}$ . The difference of squares can be factored using the rule: $\sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$ .