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TiliK225 [7]
2 years ago
7

Evaluate the following expressions if a = 2, b = 3, x = 4, and y = 5. b^2+3(2x-y)

Mathematics
1 answer:
butalik [34]2 years ago
7 0

Hi there! Hopefully this helps!

-------------------------------------------------------------------------------------------------------

<h2 /><h2>Answer: 18</h2><h2>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</h2><h2 />

First we need to substitute the value of the variable into the expression.

b^{2}+3(2x-y) = 3^{2} + 3 (2(4)-5) .

Now we need to solve 3^{2} + 3 (2(4)-5).

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

3^{2} + 3 (2(4)-5)

First, calculate 3 to the power of 2 and get 9.

9+3(2\times 4-5)=18

Multiply 2 and 4 to get 8.

9+3(8-5) =18  

Subtract 5 from 8 to get 3.    

9+3\times 3 =18  

Multiply 3 and 3 to get 9.

9+9 =18.

<h2>And the answer is, you guessed it, 18!</h2>

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A 10 pound bag of grapes costs $14.00. How much is it for 1 pound of grapes?
patriot [66]

Answer:

1.40

Step-by-step explanation:

I feel if you divide $14.00 by 10 you would get 1.40, so  I say this should be the right answer.

I apologize if I am incorrect.

3 0
2 years ago
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Alexxandr [17]
Hey, I’m pretty sure the answer is y=1/2x + 0.

To explain, we can plug the x value into the equation for all of the x values, and we will get our y value.

So the first one,

y=1/2(1) + 0 —> 1/2

The second one,

y=1/2(2) + 0 —> 1

And so forth, the rest of the equations will be correct. I hope that helps ! :D
4 0
3 years ago
In a carnival​ game, the player selects a ball one at a​ time, without​ replacement, from an urn containing twotwo purplepurple
dezoksy [38]
<span>The urn contains 2 purple balls and 4 white balls. The player pay $4 for start the game and get $1.5 for every ball drawn until one purple ball is drawn. The maximal revenue would be $7.5 when 4 white balls and 1 purple balls are drawn.
If the purple ball is p and white ball is w, t</span>he possible sample space of drawings are {p, wp, wwp, wwwp, wwwwp}

<span>1. Write down the probability distribution for the player earning

The player earning </span>for each event depends on the number of balls drawn subtracted the ticket price.<span>
p= 2/6
The player earnings would be: 1*$1.5 -$4= - $2.5
wp= (4*2)/(6*5) = 4/15
</span>The player earnings would be: 2*1.5- $4= - $1
wwp= (4*3*2)/(6*5*4)= 1/5
The player earnings would be: 3*$1.5 -$4= $0.5
wwwp= (4*3*2*2)/(6*5*4*3*2)= 2/15 
The player earnings would be: 4*$1.5 -$4= $2
wwwwp= (4*3*2*2*1)/(6*5*4*3*2*1) = 1/15
The player earnings would be: 5*$1.5 -$4=  $3.5

2. Find its expected value

The expected value would be:
chance of event * earning 
You need to combine the 5 possible outcomes from the number 1 to get the total expected value.

Total expected value= (1/3 * - 2.5)+ (4/15*-1) + (1/5*0.5) + (2/15 *2) + ( 1/15 *3.5)= 
(-12.5  -4 + 1.5 + 4 + 3.5) /15= -$7.5
This game basically a rip off.
6 0
2 years ago
Please help! Will mark brainliest! 20 points!
notsponge [240]

8      3

    -

9      4


Get common denominators.

8(4)      3 (9)

        -

9(4)      4 (9)

=

32      27

      -

36      36

=

5/36

5 0
3 years ago
18 55 -101 196 55 18 22 X-22 57 88
choli [55]

Answer:

maybe a that's my answer

8 0
2 years ago
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