Answer:
The range of T is a subspace of W.
Step-by-step explanation:
we have T:V→W
This is a linear transformation from V to W
we are required to prove that the range of T is a subspace of W
0 is a vector in range , u and v are two vectors in range T
T = T(V) = {T(v)║v∈V}
{w∈W≡v∈V such that T(w) = V}
T(0) = T(0ⁿ)
0 is Zero in V
0ⁿ is zero vector in W
T(V) is not an empty subset of W
w₁, w₂ ∈ T(v)
(v₁, v₂ ∈V)
from here we have that
T(v₁) = w₁
T(v₂) = w₂
t(v₁) + t(v₂) = w₁+w₂
v₁,v₂∈V
v₁+v₂∈V
with a scalar ∝
T(∝v) = ∝T(v)
such that
T(∝v) ∈T(v)
so we have that T(v) is a subspace of W. The range of T is a subspace of W.
In a bag of snack mix:
n = nuts d = dried fruit
n = 744g d = ???g
Ratio Nuts/Dried fruit = 12/13
This basically means that if the mix was divided in 25 parts, 12 parts would be nuts and 13 would be dried fruits
If 744 is 12 parts then 744/12 is 1 part
744/12 = 62
1 part = 62g
there are 13 parts of dried fruit
13 x 62 = 806
744g of nuts + 806g of dreid fruit = 1550g
Answer: A batch of snack mix weigh 1550g, or 1.55kg
hope it helps :)
Recall your d = rt, distance = rate * time
so... one train goes west and the goes the opposite way... alrite... so... notice, by the time 338 miles have been covered by both, it will have been "t" hours, and whatever "t" is, is the same amount of time the westbound train has been running as well as the eastbound train has been running.
now, let's say, since by "t" hours they've covered 338 altogether, so, if the westbound train has covered say "d" miles, then the eastbound train would have covered the slack from 338 and d, that is, "338 - d".

so, 2hours and 36 minutes.
Answer:
what am i supposed to help with??
Step-by-step explanation:
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