Answer:
1. D. 20, 30, and 50
2. A. 86
3. B. 94
Step-by-step explanation:
1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.
The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.
Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.
Thus:
Q1 = (85 + 87)/2 = 86
Q3 = (93 + 95)/2 = 94
IQR = Q3 - Q1 = 94 - 86
IQR = 8
Outliers in the data set are data values below the lower limit or above the upper limit.
Let's find the lower and upper limit.
Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74
The data values below the lower limit (74) are 20, 30, and 50
Let's see if we have any data value above the upper limit.
Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106
No data value is above 106.
Therefore, the only outliers of the data set are:
D. 20, 30, and 50
2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.
Thus:
Q1 = (85 + 87)/2 = 86
3. Q3 = (93 + 95)/2 = 94
Answer:
5.3125 in^2
Step-by-step explanation:
The volume of a cylinder is given by
V = pi r^2 h
V = Bh
Where B is the area of the base
25.5 = 4.8 B
Divide each side by 4.8
25.5/4.8 = B
5.3125 = B
Answer:
111.76 cm
Step-by-step explanation:
The formula for the perimeter of a triangle is given as:
Side A + Side B + Side C
Since our final answer is going to be in centimeters we have to convert the sides from inches to centimeters
Hence:
1 inch ~ 2.54 centimeters
For 12 inches
1 inch = 2.54 cm
12 inches = x
Cross Multiply
x = 12× 2.54 cm
x = 30.48 cm
For 14 inches
1 inch = 2.54 cm
14 inches = x
Cross Multiply
x = 14× 2.54 cm
x = 35.56 cm
For 18 inches
1 inch = 2.54 cm
18 inches = x
Cross Multiply
x = 18× 2.54 cm
x = 45.72 cm
Hence, the perimeter of the triangle
= 30.48 cm + 35.56 cm + 45.72 cm
= 111.76 cm
Answer:
x(x+1)²
Step-by-step explanation:
x is a common factor to all terms so the first step is to factor it out:
... x(x² +2x +1)
The quadratic factor is recognizable as the square (x+1)², so the factoring is ...
... x(x +1)²
