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Aliun [14]
2 years ago
13

Four students are trying to find the rule that translates point N(–2, –4) to N prime (2, 4). Each student’s reasoning is shown b

elow. Raheem: The rule is (x times (negative 1), y times (negative 1)) because Negative 2 times (negative 1) = 2 and Negative 4 times (negative 1) = 4. Casey: The rule is (x 2, y 4) because the image is (2, 4). Andrew: The rule is (x 4, y 0) because the coordinates are opposites. Lo: The rule is (x 4, y 8) because Negative 2 4 = 2 and Negative 4 8 = 4. Which student is correct? Raheem Casey Andrew Lo.
Mathematics
1 answer:
german2 years ago
5 0

Four students are trying to find the rule that translates point N (–2, –4) to N prime (2, 4),

According to Lo's statement : The rule is (x + 4, y + 8) because Negative 2 + 4 = 2 and Negative 4 + 8 = 4.

The answer of Lo is Correct By applying the rule (x+4, y+8) on the coordinates N(-2, -4) will give us N'(2,4)

<h3>How do find whose statement is correct?</h3>

To find that we need to first understand students' statements accordingly.

Given: Student statements as:-

  • Raheem: The rule is (x times (negative 1), y times (negative 1)) because Negative 2 times (negative 1) = 2 and Negative 4 times (negative 1) = 4.

  • Casey: The rule is (x + 2, y + 4) because the image is (2, 4).

  • Andrew: The rule is (x + 4, y + 0) because the coordinates are opposites.

  • Lo: The rule is (x + 4, y + 8) because Negative 2 + 4 = 2 and Negative 4 + 8 = 4.

Now let's understand all the statements of respective students,

According to Raheem, his statement is incorrect because it states that we can only use addition or subtraction and not multiplication in transitions.

Therefore, Raheem's answer is NOT CORRECT.

According to Casey, his statement is incorrect because after applying the rule : (x+2, y+4) on the coordinates N(-2, -4) that will give (0,0) but not N'(2,4).

Therefore, Casey's answer is NOT CORRECT.

According to Andrew, his statement is incorrect because after applying the rule: (x+4, y+0) on the coordinates N(-2, -4) that will give us (2,-4) but not N'(2,4).

Therefore, Andrew's answer is NOT CORRECT.

According to Lo, his statement is correct because after applying the rule: (x+4, y+8) on the coordinates N(-2, -4) that will give us N'(2,4).

Therefore, Andrew's answer is CORRECT.

Hence, The answer of Lo is Correct By applying the rule (x+4, y+8) on the coordinates N(-2, -4) will give us N'(2,4)

Learn more about Logical questions here;

brainly.com/question/415220

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Kobotan [32]
590,000

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. (0.5 point) We simulate the operations of a call center that opens from 8am to 6pm for 20 days. The daily average call waiting
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Answer:

The 95% t-confidence interval for the difference in mean is approximately (-2.61, 1.16), therefore, there is not enough statistical evidence to show that there is a change in waiting time, therefore;

The change in the call waiting time is not statistically significant

Step-by-step explanation:

The given call waiting times are;

24.16, 20.17, 14.60, 19.79, 20.02, 14.60, 21.84, 21.45, 16.23, 19.60, 17.64, 16.53, 17.93, 22.81, 18.05, 16.36, 15.16, 19.24, 18.84, 20.77

19.81, 18.39, 24.34, 22.63, 20.20, 23.35, 16.21, 21.73, 17.18, 18.98, 19.35, 18.41, 20.57, 13.00, 17.25, 21.32, 23.29, 22.09, 12.88, 19.27

From the data we have;

The mean waiting time before the downsize, \overline x_1 = 18.7895

The mean waiting time before the downsize, s₁ = 2.705152

The sample size for the before the downsize, n₁ = 20

The mean waiting time after the downsize, \overline x_2 = 19.5125

The mean waiting time after the downsize, s₂ = 3.155945

The sample size for the after the downsize, n₂ = 20

The degrees of freedom, df = n₁ + n₂ - 2 = 20 + 20  - 2 = 38

df = 38

At 95% significance level, using a graphing calculator, we have; t_{\alpha /2} = ±2.026192

The t-confidence interval is given as follows;

\left (\bar{x}_{1}- \bar{x}_{2}  \right )\pm t_{\alpha /2}\sqrt{\dfrac{s_{1}^{2}}{n_{1}}+\dfrac{s_{2}^{2}}{n_{2}}}

Therefore;

\left (18.7895- 19.5152 \right )\pm 2.026192 \times \sqrt{\dfrac{2.705152^{2}}{20}+\dfrac{3.155945^2}{20}}

(18.7895 - 19.5125) - 2.026192*(2.705152²/20 + 3.155945²/20)^(0.5)

The 95% CI = -2.6063 < μ₂ - μ₁ < 1.16025996668

By approximation, we have;

The 95% CI = -2.61 < μ₂ - μ₁ < 1.16

Given that the 95% confidence interval ranges from a positive to a negative value, we are 95% sure that the confidence interval includes '0', therefore, there is sufficient evidence that there is no difference between the two means, and the change in call waiting time is not statistically significant.

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Step-by-step explanation:

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