Answer:
1.5
Explanation:
Given that :
Compound A and B are formed from Sulfur + Oxygen.
Compound A :
6g sulfur + 5.99g Oxygen
Compound B:
8.6g sulfur + 12.88g oxygen
Comparing the ratios :
Compound A:
S : O = 6.00 : 5.99
S/0 = 6.0g S / 5.99g O
Compound B :
S : O = 8.60 : 12.88
S / O = 8.60g S / 12.88g O
Mass Ratio of A / mass Ratio of B
(6.0g S / 5.99g O) ÷ (8.60g S / 12.88g O)
(6.0 g S / 5.99g O) × (12.88g O / 8.60g S)
(6 × 12.88) / (5.99 × 8.60)
= 77.28 / 51.514
= 1.50017
= 1.5
Answer:
Learn from their experiment and know the possible results from trial and error
The total atomic number must be the same on each side. The total mass number must be the same on both side.
<span>On the RHS, for the mass number, we have 257 + 4 = 261 (the 4 comes from the 4 neutrons). That means the mass number of the missing piece on the LHS is 261 - 247 = 14. </span>
<span>One the RHS, for the atomic number we have a total of 104 since the 4 neutrons are all neutral. On the LHS, we have this: 104 - 98 = 6. </span>
<span>The missing piece is a nucleus of carbon 14. Done in your style, it is 14/6C</span>
Answer:
m = 79.1 grams
Explanation:
Given that,
Density, d = 2.26 g/mL
Volume occupies, V = 35 mL
We need to find the mass of the substance. We know that the density of an object is equal to the mass per unit volume. So,
d = m/V
So, the mass of the substance is 79.1 grams.
Answer:
Given : No. Of moles = 1.5
To calculate : no. Of molecules =N
We know that moles = N / 6.022 x 10²³
Therefore, 1.5 x 6.022 x 10²³ = N
Hence N = 9.0330x 10²³ molecules
