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Olin [163]
2 years ago
8

Determine the mass (in g) of a substance, with a density of 2.26 g/mL, that occupies 350.0 mL.

Chemistry
1 answer:
Andreyy892 years ago
6 0

Answer:

m = 79.1 grams

Explanation:

Given that,

Density, d = 2.26 g/mL

Volume occupies, V = 35 mL

We need to find the mass of the substance. We know that the density of an object is equal to the mass per unit volume. So,

d = m/V

m=d\times V\\\\m=2.26\ g/mL\times 35\ mL\\\\m=79.1\ g

So, the mass of the substance is 79.1 grams.

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Answer:

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A car can accelerate from a standstill to 100 km/h [E] in 9.60s. calculate the average acceleration
Lelu [443]

Answer:

Acceleration is :

a = 2.89 m/s2

Explanation:

Acceleration : It is the change in the velocity of the object per unit time.

The object starts from the rest , so the initial velocity of the object is zero.

Initial velocity , u = 0

Final velocity = 100 km/h

Change the velocity to m/s because[ time unit is in second(9.60 s)]

1 km = 1000 m

1 hour = 60 x 60 sec = 3600 sec

1km/h=\frac{1000}{3600}m/s

1km/hr=\frac{5}{18}

100km/hr=\frac{5}{18}\times 100

v=\frac{5}{18}\times 100

v = 27.78 m/s

u = 0 m/s

time = 9.60 s

The acceleration"a" is calculated using :

a=\frac{v-u}{t}

a=\frac{27.78-0}{9.6}

a=\frac{27.78}{9.6}

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5 0
2 years ago
How do you use pedigrees to determine and explain the inheritance of traits?
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What is the ph of a soft drink in which the major buffer ingredients are 6.6 g of nah2po4 and 8.0 g of na2hpo4 per 355 ml of sol
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The Relative Formula Mass of NaH2PO4 is 120 g/mol
Therefore, the number of moles = 6.6/120
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[H2PO4-] = Number of moles oof H2PO4-/Volume of the solution in L
  = 0.055/ ( 355 ×10^-3)
  = 0.155 M
Na2HPO4 undergoes complete dissociation as follows;
Na2HPO4 (aq)= 2Na+ (aq) + HPO4^2- (aq)

1 mole of Na2HPO4 = 142 g/mol
Therefore; number of moles = 8.0/142
                                             = 0.0563 moles
 [HPO4 ^-2] is given by no of moles HPO4^2- /volume of the solution in L
     = 0.0563/(355×10^-3)
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Ka of H2PO4- = 6.20 × 10^-8
 [H+] =Ka*([H2PO4-]/[HPO4(2-)]
        = (6.20 ×10^-8)×(0.155/0.1586)
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pH = - log[H+]
     = - log (6.059×10^-8)
     = 7.218

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3 years ago
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