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3 years ago

Solve 4(t + 1) = 6t -1

Mathematics

2 answers:

mel-nik [20]3 years ago

6 0

4(t + 1) = 6t -1

Multiply the bracket by 4

4(t)+4(+1)=6t-1

4t+4=6t-1

Move +6t to the other side. Sign changes from +6t to -6t.

4t-6t+4=6t-6t-1

-2t+4=-1

Move +4 to the other side. Sign changes from +4 to -4.

-2t+4-4=-1-4

-2t=-5

Divide by -2

-2t/-2=-5/-2

Cross out -2 and -2, divide by -2 and then becomes t.

t=5/2 or t= 2 1/2 or t=2.5

Answer: t=5/2, t=2 1/2, t=2.5

lyudmila [28]3 years ago

4 0

Answer:

t=5/2

Step-by-step explanation:

4(t + 1) = 6t -1

=>4t+4=6t-1

=>6t-4t=4+1

=>2t=5

=>t=5/2

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Martin throws a ball straight up in the air. the equation h(t) = -16t^2 + 40t + 5 gives the height of the ball, in feet, t secon

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Answer:

2.62 seconds

Step-by-step explanation:

Let

t ----> the time in seconds

h(t) ----> he height of the ball, in feet

we have

$h(t)=-16t^2+40t+5$

we know that

When the ball hits the ground, the height is equal to zero

$-16t^2+40t+5=0$

The formula to solve a quadratic equation of the form

$at^{2} +bt+c=0$

is equal to

$t=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-16t^2+40t+5=0$

$a=-16\\b=40\\c=5$

substitute in the formula

$t=\frac{-40\pm\sqrt{40^{2}-4(-16)(5)}} {2(-16)}$

$t=\frac{-40\pm\sqrt{1,920}} {-32}$

$t=\frac{-40+\sqrt{1,920}} {-32}=-0.12\ sec$

$t=\frac{-40-\sqrt{1,920}} {-32}=2.62\ sec$

therefore

The solution is t=2.62 seconds

4 0

3 years ago

Solve 4(t + 1) = 6t -1​

Solve 4(t + 1) = 6t -1