<span>
<span>Speed
is calculated as distance covered, divided by the time taken to cover that
distance. In this case, the sales person covered 50KM in 45minutes (which can
also be expressed as 3/4 hours). To calculate the speed he used to cover this
distance, we divide the distance covered by the time taken. So 50km/3/4hours.
This gives us 66.67km/hr. In order to calculate the amount of time the
salesperson used to travel from the office to the sales person, we calculate
as follows 250km/66.67km/hr. This gives us a total of 3.75 hours or 3 hours 45 minutes.</span></span>
Answer:
A
Step-by-step explanation:
Here, we want to write the final formula for the equation after performing the given transformations
Reflection on the y-axis means the x-axis value will change sign
that will give:
y = -x^1/3
Transition of 3 units in the positive x axis
mathematically, we are adding 3 to x
so we have
y = -(x+3)^1/3
4 units in the negative y direction means we are subtracting 4 from the whole equation
That means;
y = -(x + 3)^1/3 - 4
This shows that the first option is right
Answer:
52 sq un
Step-by-step explanation:
Formula for slope: ![\frac{y2 - y1}{x2 - x1}](https://tex.z-dn.net/?f=%5Cfrac%7By2%20-%20y1%7D%7Bx2%20-%20x1%7D)
y₂: 6
y₁: 8
x₂: 1
x₁: -2
Plug them into the slope equation:
![\frac{6 - 8}{1 - (-2)}](https://tex.z-dn.net/?f=%5Cfrac%7B6%20-%208%7D%7B1%20-%20%28-2%29%7D)
--> ![\frac{-2}{1 + 2}](https://tex.z-dn.net/?f=%5Cfrac%7B-2%7D%7B1%20%2B%202%7D)
---> ![-\frac{2}{3}](https://tex.z-dn.net/?f=-%5Cfrac%7B2%7D%7B3%7D)
The slope is
.
Answer:
The correct option is (b).
Step-by-step explanation:
If X
N (µ, σ²), then
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z
N (0, 1).
The distribution of these z-variate is known as the standard normal distribution.
The mean and standard deviation of the active minutes of students is:
<em>μ</em> = 60 minutes
<em>σ </em> = 12 minutes
Compute the <em>z</em>-score for the student being active 48 minutes as follows:
![Z=\frac{X-\mu}{\sigma}=\frac{48-60}{12}=\frac{-12}{12}=-1.0](https://tex.z-dn.net/?f=Z%3D%5Cfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3D%5Cfrac%7B48-60%7D%7B12%7D%3D%5Cfrac%7B-12%7D%7B12%7D%3D-1.0)
Thus, the <em>z</em>-score for the student being active 48 minutes is -1.0.
The correct option is (b).