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BlackZzzverrR [31]
3 years ago
8

80 Hundreds = ____ Thousandths

Mathematics
1 answer:
allsm [11]3 years ago
3 0
The answer would be 0.8, because 800 hundreds go into 8 thousandths, but there is only 80 hundreds, so the answer is 0.8 thousandths.
Answer: 0.8 thousandths

PLZ MARK MINE THE BRAINLIEST ANSWER!!!
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Jannetta and George each made apple juice. Jannetta mixed 12 fluid ounces of apple concentrate with every quart of water to make
Karolina [17]

Answer:

answer "C"

Step-by-step explanation:

5 0
3 years ago
Find the volume of the rectangular prism that has a width of 3 cm, a length of 8cm, and a hight of 7cm
Brut [27]

Answer:

V = 168 cm^3

Step-by-step explanation:

L length - 8cm

W width - 3 cm

H height - 7 cm    

V = w h l   (Right rectangular prism)

Download txt
8 0
3 years ago
Factor completely 18x2 − 21x −15. 3(2x 1)(3x − 5) 3(2x − 5)(3x 1) 3(2x − 1)(3x 5) 3(6x 1)(x − 5).
sergeinik [125]

The factor of the 18x^{2} -21x-15 will be 3(3x-5)(2x+1).

<h3>What will be the factor of  18x^{2} -21x-15 ?</h3>

Given quadratic equation is 18x^{2} -21x-15

By taking 3 common from whole of the equation it becomes.

3(6x^{2} -7x-5)

now by factorization equation will be.

3(6x^{2} -10x+3x-5)

3[(2x(3x-5)+1(3x-5)]

Taking (3x-5) common from whole equation it will become

3(3x-5)(2x+1).

Hence the factor of the 18x^{2} -21x-15 will be 3(3x-5)(2x+1).

To know more about factorization follow.

brainly.com/question/25829061

3 0
2 years ago
Va rog e urgent am nevoie de raspuns
Lady_Fox [76]

Answer: 4

<u>Explanation:</u>

f(x) = 2x - 1

f(√2) = 2√2 - 1

f(1) = 2(1) - 1

     =  2 - 1

     =     1

f(√3)  = 2√3 - 1

*******************************************************

\frac{f(\sqrt{2})-f(1)}{\sqrt{2}-1} +\frac{f(\sqrt{3})-f(\sqrt{2})}{\sqrt{3}-\sqrt{2}}

= \frac{(2\sqrt{2}-1)-1}{\sqrt{2}-1} +\frac{(2\sqrt{3}-1)-(2\sqrt{2}-1)}{\sqrt{3}-\sqrt{2}}

= \frac{2\sqrt{2}-2}{\sqrt{2}-1} +\frac{2\sqrt{3}-2\sqrt{2}}{\sqrt{3}-\sqrt{2}}

= \frac{2\sqrt{2}-2}{\sqrt{2}-1}(\frac{\sqrt{2}+1}{\sqrt{2}+1})+\frac{2\sqrt{3}-2\sqrt{2}}{\sqrt{3}-\sqrt{2}}(\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}+\sqrt{2}})

= \frac{4+2\sqrt{2}-2\sqrt{2}-2}{2 - 1} + \frac{6 +2\sqrt{6}-2\sqrt{6}-4}{3-2}

= \frac{2}{1} +\frac{2}{1}

= 4

3 0
3 years ago
Differentiate the following equation
Bingel [31]

Answer:

\frac{dy}{dx} = \frac{4}{1-x}

Step-by-step explanation:

    y = 3 - 4ln(1 - x)

⇒ \frac{dy}{dx} =3\frac{d}{dx} -4ln(1-x)\frac{d}{dx}

⇒ \frac{dy}{dx} =0 -4ln(1-x)\frac{d}{dx}

⇒ \frac{dy}{dx} =0 -4(\frac{1}{1-x})\times-1

⇒ \frac{dy}{dx} = \frac{4}{1-x}

4 0
3 years ago
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