1. You can expand the coefficients to yield 6, and add the powers since the bases are the same (ie A)
2. y⁻² can also be rewritten as 1/y², so it becomes 1/y² · 1/y⁵ = 1/y⁷ (ie C)
3. Only the x is affected by the power.
4. y = 3·5ˣ doesn't change in slope, so it essentially is similar to a 5ˣ graph.
5. Should be pretty straight forward.
6. Should be pretty straight forward.
7. Should be pretty straight forward.
8. Since x is the length of the border, calculate the area of the frame and subtract that from the area of the square painting. (Remember that the length of the square painting is x - 8, not x - 4)
9. Should be pretty straight forward.
11 - 25 are pretty much similar to each other.
If you have trouble, let me know and I'll walk you through it.
That’s right they both equal 67
To calculate hypothenuse you use the formula a^2+b^2=c^2 where c is the length of the hypothenuse.
1. 5^2+7^2=c^2
2.25+49=74
3. Now you will square root the 74
4. The hypothenuse is equal to 8.6
Answer:
AC = 6
Step-by-step explanation:
y is the dimension of the horizontal segment (see the attached image).
The hypotenuses are the same dimension, so:
(x+4)^2=(x/2)^2+y^2
(3x-8)^2=(x/2)^2+y^2
So,
(x+4)^2 = (3x-8)^2
x+4 = 3x-8
x-3x = -8-4
-2x = -12
x = 6
And x is the dimension of the segment AC.
