The equivalents of the given compound inequality are x > 3 and x ≤ 5.2 OR 3 < x ≤ 5.2
<h3>Solving inequalities </h3>
From the question, we are to determine the equivalent form of the compound inequality
We will solve the given compound inequality
The given inequality is
−22 > −5x − 7 ≥ −33
We can write that
−22 > −5x − 7 AND −5x − 7 ≥ −33
Solving −22 > −5x − 7
5x > -7 +22
5x > 15
x > 15/5
x > 3
Also,
Solve −5x − 7 ≥ −33
−5x ≥ −33 +7
-5x ≥ -26
x ≤ -26/-5
x ≤ 5.2
Hence, the equivalents of the given compound inequality are x > 3 and x ≤ 5.2 OR 3 < x ≤ 5.2
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Answer:
b = a + 3.75
Step-by-step explanation:
a = 4b - 15
You are solving for b. Isolate the b. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. First, add 15 to both sides
a (+15) = 4b - 15 (+15)
a + 15 = 4b
Next, divide 4 from both sides. Remember to divide from all terms.
(4a + 15)/4 = (4b)/4
b = (4a)/4 + (15)/4
b = a + 15/4
b = a + 3.75 is your answer
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Answer:
x = 14
Step-by-step explanation:
Using Pythagoras' identity in the right triangle
x² + x² = (14 )²
2x² = 392 ( divide both sides by 2 )
x² = 196 ( take the square root of both sides )
x = = 14
Thus the congruent legs are 14 cm
-|-3p|
-|-3(5)|
= -|-15|
= -(15)
= -15
The value of the expression when p = 5 is -15.
Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean and standard deviation is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
In this problem, the mean and the standard deviation are given, respectively, by:
.
The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:
Z = 1.71
Z = 1.71 has a p-value of 0.9564.
1 - 0.9564 = 0.0436.
0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.
More can be learned about the normal distribution at brainly.com/question/24663213
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