How do you do this???????????????

Mathematics

1 answer:

Lostsunrise [7]3 years ago

6 0

To find the number of divisors, including 1 and m, add 1 to the exponent of each of the prime factors and multiply those sums together.
.. number of divisors = (2 +1)*(1 +1)*(3 +1) = 3*2*4 = 24

When you exclude 1 and m, you have 22 divisors remaining.

Selection D is appropriate.

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Percy works two part-time jobs to help pay for college classes. On Monday, he works 3 hours at the library and 2 hours at the co

laila [671]

For the answer to the two questions above,
3x + 2y = 36.50 (I)
2x + 5y = 50 (II)
Eliminating x from the two equations by subtraction:
first we multiply equation I by 2 and equation II by 3
6x + 4y = 73
6x + 15y = 150
Subtracting the two,
-11y = -77
y = 7
He earns $7 at the coffee cart
Substituting y into equation I,
3x + 14 = 36.5
x = $7.50

So we can conclude that, he earns a greater wage of $7.50 at the library,

6 0

3 years ago

Read 2 more answers

Given:B is the midpoint of AC. Complete the statement. If AB = 7,then BC = _____, and AC = ____.

Alex73 [517]

Midpoint

We know AC is a segment and B is its midpoint. This means the length of the segment AB is half the length of the segment AC. This also means the length of the segment BC is half the length of AC, and equal to AB.

This can be visualized as follows:

Since AB=7, then BC = 7 and AC=AB+BC = 14

Answer: BC = 7, and AC=!4

5 0

1 year ago

Martha is late for class, so she races her 75 kg body up a 4.0 meter flight of stairs in only 2.3 seconds. What is Martha’s powe

vovangra [49]

Answer:

$1.3\cdot 10^3\text{ J}$

Step-by-step explanation:

Power is defined by work over time. In physics, work can be defined as the energy transferred over from an applied force over some distance. As a formula:

$W=Fd$ , where F = force applied and d = distance that force is applied over.

*It is worth noting that F must be parallel to the distance travelled. If it is perpendicular, no work is done, and if it is at an angle, find the parallel component and use that for F.

In this case, the force applied must counter the force of gravity on Martha, which is given by $F_g=mg$ , where m = Martha's mass and g = gravitational constant 9.8 m/s/s. Therefore, $F_g=75\cdot 9.8=735\text{ N}$ . Since she raises her body 4.0 meters, the work done must be $W=Fd=735\cdot 4=2940\text{ J}$ .