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Kobotan [32]
2 years ago
15

Question 18(Multiple Choice Worth 1 points)

Mathematics
1 answer:
Y_Kistochka [10]2 years ago
4 0

Answer:

B

Step-by-step explanation:

2^2 x 2^3 = 2^5

2^5/2^4 = 2^1

You might be interested in
The sum of two numbers is "-1" One number is 12 more than the other one. Find the numbers.
ruslelena [56]

Answer:

x = 5.5

y = - 6.5

Step-by-step explanation:

Let one of the numbers = x

Let the other number = y

x + y = - 1

x = y + 12    Put the second equation into the first one

y + 12 + y = - 1       Subtract 12 from both sides

y + y = - 1 - 12        Combine both left and right sides

2y = - 13                Divide by 2

2y/2 = - 13/1

y = - 6.5

x + y = - 1

x - 6.5 = - 1            Add 6.5 to both sides

x = 5.5

7 0
3 years ago
Please help I need due ....
seropon [69]

Answer:

The answer is 22 2/5

Step-by-step explanation:

So the correct is B

6 0
2 years ago
How do you put 943,261,586 with base ten numbers
Citrus2011 [14]

Answer:

(9 \times 10^{8}) + (4 \times 10^{7}) + (3 \times 10^{6}) + (2 \times 10^{5}) +  (6 \times 10^{4}) +  (10^{3}) +  (5 \times 10^{2}) +  (8 \times 10) + (6 \times 10^{0})

Step-by-step explanation:

How do you put 943,261,586 with base ten numbers

943,261,586  =  

900,000,000 + 40,000,000 + 3,000,000 + 200,000 + 60,000 + 1,000 + 500 + 80 +6 =

(9 \times 10^{8}) + (4 \times 10^{7}) + (3 \times 10^{6}) + (2 \times 10^{5}) +  (6 \times 10^{4}) +  (10^{3}) +  (5 \times 10^{2}) +  (8 \times 10) + (6 \times 10^{0})

8 0
2 years ago
An expression is shown below.<br> (3)(x<br> What is the product of the two factors?
Reika [66]

Answer:

3x

Step-by-step explanation:

3 . x is 3x

7 0
3 years ago
Isabel wrote this mystery problem. The quotient is multiple of 6. The dividend is multiple of 9. The divisor is a factor of 12.
Marina86 [1]

Answer:

Consider the expression q=\frac{a}{b}. q is called the quotient, a is is the dividend and b is the divisor.

Since q is a multiple of 6, then q has the form q=6k for some integer k.

Since a is a multiple of 9, then a has the form a=9s for some integer s.

Since b is a factor of 12, then if 12 can be expressed of the form 12=c*b, for c an integer. Then b has the form b=\frac{12}{m}

Replacing the preview expression in the initial expression we obtain:

6k=\frac{9s}{\frac{12}{m}}=\frac{9sm}{12}\\6*12k=9sm\\72k=9sm\\72k-9sm=0

Then 72k-9sm=0,\; for \; k,s,m\in \mathbb{Z} is a equation to Isabel's problem.

3 0
2 years ago
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