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3 years ago

What is the measure of LXZW? 850 150° Y 65° 95 Z 215° W 30°

Mathematics

1 answer:

Semenov [28]3 years ago

3 0

Answer:

so the answer is 95°

Step-by-step explanation:

The two angles on a line add up to 180° or are supplementary, so we can find the inside angle x by doing 180-150=30°. Now that we know inside x is 30, if we add 30+65, we get 95, and 180-95=85°. Then to find angle xzw, just do 180-85 to get 95°.

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Step-by-step explanation:

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A sociologist was investigating the ages of grandparents of high school students. From a random sample of 10 high school student

umka2103 [35]

Answer:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_{M}= 69.8$ represent the mean for the age of grandmother

$\bar X_{F}= 71.6$ represent the mean for the age of grandfather

$s_{M}= 8.38$ represent the sample deviation for the age of grandmother

$s_{F}= 6.65$ represent the sample deviation for the age of grandfather

$n_M = n_F= 10$

Solution to the problem

For this case the confidence interval is given by:

$(\bar X_{M} -\bar X_F) \pm t_{\alpha/2} \sqrt{\frac{s^2_M}{n_M} +\frac{s^2_F}{n_F}}$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_M +n_F-2=10+10-2=18$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that $t_{\alpha/2}=2.101$

And replacing we got:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

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3 years ago

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3 years ago

Y=4x+3 table of ordered pairs

lara31 [8.8K]

Answer:

X:1 2 3 4 5 Y:7 11 15 19 23.

Step-by-step explanation:

We just need to put in the values of x into the equation: y = 4x + 3.

x = 1:

y = 4(1) + 3

= 4 + 3

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x = 2:

y = 4(2) + 3

= 8 + 3

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x = 3:

y = 4(3) + 3

= 12 + 3

y = 15

x = 4:

y = 4(4) + 3

= 16 + 3

y = 19

x = 5:

y = 4(5) + 3

= 20 + 3

y = 23

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