Ask question

Ask question

All categories

3 years ago

12

A newly-planted tree needs to be staked with three wires. Each wire is attached to the trunk 3 ft. above the ground, and then an

chored to the ground 4 ft. from the base of the tree. How much wire is needed for 6 trees?

1 answer:

jolli1 [7]3 years ago

6 0

Multiply 3 by 6 to get 18 the rest of it is extra information

3*6 = 18

You might be interested in

Mrs.Harris has a coupon for a 25% on any one book. The regular cost of the book she wants to buy is $32. What will be the discou

makkiz [27]

$\frac{25}{100}*32=8$

The discount will be 8$

7 0

3 years ago

Read 2 more answers

Paul drinks 6 cups of coffee each day. Each cup contains 275 milliliters of coffee. How

scZoUnD [109]

<h3>Answer: 11.55 liters</h3>

=================================================

Work Shown:

275 mL = 275/1000 = 0.275 L

1 cup = 0.275 L

6 cups = 6*0.275 L = 1.65 L

He drinks 1.65 L per day, so over 7 days he drinks a total of 7*1.65 = 11.55 liters.

5 0

3 years ago

Read 2 more answers

Consider the following.

saul85 [17]

Answer:

Step-by-step explanation:

jack is correct

3 0

3 years ago

1. What is the slope of a line that passses through (-1,-5) and (6, 8)?

elena-s [515]

Answer:

Step One: Identify two points on the line.

Step Two: Select one to be (x1, y1) and the other to be (x2, y2).

Step Three: Use the slope equation to calculate slope.

4 0

3 years ago

Calculate the frequency in hertz of photons of light with energy of 8.10 × 10-19 J.

stira [4]

The Planck–Einstein relation $E=hv$ gives that E, the photon energy, is equal to h, Planck's constant, times <span>ν</span>, the frequency.

We can solve the equation in terms of frequency to get
$v= \dfrac{E}{h}$

We substitute our given energy, $8.10 \times 10^{-19} J$ , and Planck's constant, $6.626 \times 10^{-34} Js$ .

$v= \dfrac{8.10 \times 10^{-19} J}{6.626 \times 10^{-34} Js}=1.22 \times 10^{15} s^{-1}=1.22 \times 10^{15} Hz$

5 0

3 years ago