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uranmaximum [27]

3 years ago

12

It cost $350 to carpet an 8‘ x 10‘ room. At this rate how many dollars would it cost to put the same carpeting in a 24‘ x 30‘ ro

om

1 answer:

RUDIKE [14]3 years ago

4 0

Answer:

$1050

Step-by-step explanation:

The total area of the second space is three times the first one, thus the price increases to triple the amount.

You might be interested in

Base ten blocks to find 10000

pashok25 [27]

The answer would be 100 blocks

7 0

3 years ago

The spray from a sprinkler reaches 21 feet from the sprinkler and creates a circle as it spins. What is the circumference of the

Snezhnost [94]

Answer

D: 132 ft

C= π2r

So, take pi and multiply that by two..

π2= 6.28

Now, take your radius and multiply it by 6.28.

21 x 6.28= 131.88

Round it two the nearest whole number, which is 132!

Hope this helps!

3 0

3 years ago

Read 2 more answers

If f(x, y, z) = x sin(yz), (a) find the gradient of f and (b) find the directional derivative of f at (2, 4, 0) in the direction

valentina_108 [34]

Answer:

a) $\nabla f(x,y,z) = \sin{yz}\mathbf{i} + xz\cos{yz}\mathbf{j} + xy \cos{yz}\mathbf{k}$ .

b) $Du_{f}(2,4,0) = -\frac{8}{\sqrt{11}}$

Step-by-step explanation:

Given a function $f(x,y,z)$ , this function has the following gradient:

$\nabla f(x,y,z) = f_{x}(x,y,z)\mathbf{i} + f_{y}(x,y,z)\mathbf{j} + f_{z}(x,y,z)\mathbf{k}$ .

(a) find the gradient of f

We have that $f(x,y,z) = x\sin{yz}$ . So

$f_{x}(x,y,z) = \sin{yz}$

$f_{y}(x,y,z) = xz\cos{yz}$

$f_{z}(x,y,z) = xy \cos{yz}$ .

$\nabla f(x,y,z) = f_{x}(x,y,z)\mathbf{i} + f_{y}(x,y,z)\mathbf{j} + f_{z}(x,y,z)\mathbf{k}$ .

$\nabla f(x,y,z) = \sin{yz}\mathbf{i} + xz\cos{yz}\mathbf{j} + xy \cos{yz}\mathbf{k}$

(b) find the directional derivative of f at (2, 4, 0) in the direction of v = i + 3j − k.

The directional derivate is the scalar product between the gradient at (2,4,0) and the unit vector of v.

We have that:

$\nabla f(x,y,z) = \sin{yz}\mathbf{i} + xz\cos{yz}\mathbf{j} + xy \cos{yz}\mathbf{k}$

$\nabla f(2,4,0) = \sin{0}\mathbf{i} + 0\cos{0}\mathbf{j} + 8 \cos{0}\mathbf{k}$ .

$\nabla f(2,4,0) = 0i+0j+8k=(0,0,8)$

The vector is $v = i + 3j - k = (1,3,-1)$

To use v as an unitary vector, we divide each component of v by the norm of v.

$|v| = \sqrt{1^{2} + 3^{2} + (-1)^{2}} = \sqrt{11}$

So

$v_{u} = (\frac{1}{\sqrt{11}}, \frac{3}{\sqrt{11}}, \frac{-1}{\sqrt{11}})$

Now, we can calculate the scalar product that is the directional derivative.

$Du_{f}(2,4,0) = (0,0,8).(\frac{1}{\sqrt{11}}, \frac{3}{\sqrt{11}}, \frac{-1}{\sqrt{11}}) = -\frac{8}{\sqrt{11}}$

6 0

3 years ago

Are the expressions 8a - 3b - (2a + 4b) and 6a + b equivalent?

Margaret [11]

Answer:

No.

Step-by-step explanation:

Let's start by simplifying the first expression:

$8a-3b-(2a+4b)$

Remove the parentheses:

$8a-3b-(2a)-(4b)\\8a-3b-2a-4b$

Combine like terms:

$8a-2a-3b-4b\\6a-7b$

$6a-7b\neq 6a+b$ (Assuming that none of the variables are equivalent to 0)

3 0

2 years ago

Solve the quadratic equation. 22 – 9 = 16

Colt1911 [192]

Answer:

22-9=16

so,

22-9

is 16

then you would take

16=16

so, you would have to divide the 2 numbers

then 1 is your answer

Step-by-step explanation:

6 0

3 years ago