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3 years ago

(x2 - 2)(-5x2 + x) = (x2)(-5x²)+(x2)(x)+(-2)(-5x2) + (-2)(x) is an example of:

Mathematics

1 answer:

KatRina [158]3 years ago

4 0

Answer:

FOIL

Step-by-step explanation:

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Find the area of the rhombus. d1 = 14 m; d2 = 18 m The area of the rhombus is ? m2.

xxTIMURxx [149]

Answer:

Area of rhombus = 126 m²

Explanation:

We are given that the two diagonals of the rhombus are:

D₁ = 14 meters and D₂ = 18 meters

The area of the rhombus using its diagonals can be calculated using the following rule:

$Area = \frac{D_1 * D_2}{2}$

Substitute with the given values to get the area as follows:

$Area = \frac{14*18}{2}=126 m^2$

Hope this helps :)

8 0

2 years ago

Read 2 more answers

Help me with this!! I will mark Brainliest ❤️

soldi70 [24.7K]

28 because it is qhal

5 0

2 years ago

An artificial soccer pitch is 91 meters long and 43 meters wide. If the cost of the pitch is AED 20 per square meter. What is th

Novosadov [1.4K]

The Cost of installing the artificial soccer pitch is $5360

A rectangle is a quadrilateral (has four sides and four angles) in which opposite sides are parallel and equal.

The soccer pitch us rectangle in shape. Hence:

Perimeter of soccer pitch = 2(length + width) = 2(91 + 43) = 268 meters

Cost of installing the pitch = $20 per meter * 268 meters = $5360

The Cost of installing the artificial soccer pitch is $5360

Find out more on perimeter at: brainly.com/question/16596982

6 0

2 years ago

Original price: $150; Markdown:40%(show work please)

zepelin [54]

Original price is $150 so you times 150 by 0.40
150 x 0.40 = 60
So you take the $150 and you subtract $60 from $150
150 - 60 = 90
So the answer is $90

8 0

3 years ago

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

olchik [2.2K]

Answer:

14.52 seconds.

Step-by-step explanation:

We have been given that the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation $y=-16x^2+224x+121$ . We are asked to find the time, when the rocket will hit the ground.

We know that the rocket will hit the ground, when height will be 0. So to find the time when rocket will hit the ground, we will substitute $y=0$ in our given equation as: