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Answer:
Step-by-step explanation:
Given that St. Mary's Church is holding a raffle in which 1172 tickets have been sold at a cost of $2.00 each.
Three prizes will be awarded: 1 for S500;1 for $250; 1 for $125.
Thus total number of tickets = 1172
Of these prize winning are 3
i.e. Tickets Prize $ Net win amount Prob Net win amt*prob
1 500 (500-2) =448 1/1172 448/1172
1 250 (250-2) =248 1/1172 248/1172
1 125 (125-2) =123 1/1172 123/1172
1169 0 (0-2) = -2 1169/1172 -2338/1172
Expected value = Total -1519/1172
=-1.296
-14>2x>18
Hope this helps!
Let x = the number of dimes
Let y = the number of pennies.
There are 8 coins, therefore
x + y = 8 (1)
The coins are worth 17 cents, therefore
10x + y = 17 (2)
Subtract equation (1) from equation (2).
10x + y - (x + y) = 17 - 8
9x = 9
x = 1
From (1), obtain
y = 8 -x = 8 - 1 = 7
Answer: 1 dime, 7 pennies.
