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Sergeu [11.5K]
3 years ago
7

Suppose there are 7 roads connecting town a to town b and 8 roads connecting town b to town c. In how many ways can a person tra

vel from a to c via b ?
Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
3 0

Answer:

7\cdot{8}=56

Step-by-step explanation:

In combinatorics, the rule of product states that if there are x ways of doing one thing and y ways of doing another thing, then there are x\cdot{y} ways of performing both actions.

In this case, if there are 7 ways of getting from town A to town B, and 8 ways of getting from town B to town C, then there are 7\cdot{8}=56 ways of getting from town A to town C via town B.

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Step-by-step explanation:

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Find the error in the following sample of work, if one exists.
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Answer:

D. There is no mistake.

Step-by-step explanation:

The following lines show the process of factorization by using common factor.

<u>Line 1:</u>

In line 1, the equation is given and is completely fine.

y^{2}+8xy+2y+16x=0

The only thing missing was equate to zero, but the options below talk about correct factors only, therefore this can't be considered as a mistake and can be ignored completely.

<u>Line 2:</u>

In line 2, the terms are grouped, from which we can factor out common terms.

(y^{2}+8xy)+(2y+16x)=0

This is also fine.

<u>Line 3:</u>

In line 3, the common term y is taken out from group 1 and 2 from other group.

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which is exactly what is given in line 3.

<u>Line 4:</u>

In line 4 the common factors can be seen and easily split into 2 factors.

(y+2)(y+8x)=0

which is exactly what is given in line 4.

Options:

A. The grouping is correct in line 2. So this option is does not hold.

B. Common factor was factored correctly from group 1. So this option does not hold.

C. Common factor was factored correctly from group 2. So this option does not hold.

D. There is no mistake. This is correct. Thus we choose this option as correct answer.

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