Answer:
It is irrational because it can not be represented as a fraction of two integers
Step-by-step explanation:
Given
![H = \sqrt[3]5](https://tex.z-dn.net/?f=H%20%3D%20%5Csqrt%5B3%5D5)
Required
Why is the area irrational?
First, we need to calculate the area
![Area = \frac{1}{2}(3.6 + 12\frac{1}{3}) * \sqrt[3]5](https://tex.z-dn.net/?f=Area%20%3D%20%5Cfrac%7B1%7D%7B2%7D%283.6%20%2B%2012%5Cfrac%7B1%7D%7B3%7D%29%20%2A%20%5Csqrt%5B3%5D5)
<em>It is irrational because it can not be represented as a fraction of two integers</em>
Answer:
(x/2) + 15 = 5 + 3x
Step-by-step explanation:
Follow the steps in the equation. X is your number. First you halve it, then you add 15. Next, set it equal to the other side. The second side is 5 + (because it is the sum) and 3x (the product of 3 and x means multiply them)
Gradient =2 because the slope is 2 units. Y-intercept = -2 because it crosses the y-line at -2.
This is what the graph would look like
You can answer this problem using the midpoint formula, but we can work out the 4th vertex by just logically thinking it through by first drawing out the rhombus on an x-y coordinate plane. I wrote the answer out on paper since it is easier than typing. Let me know if you have any questions.
