Ask question

Ask question

All categories

3 years ago

12

Antonio drove 26 miles north and then drives West at the end of his Drive is determined that he is 50 miles from where he starte

d how far was did he drive

1 answer:

EleoNora [17]3 years ago

8 0

25 because you subtract 50 from 25

You might be interested in

How to find pattern and equation of y = 3x + 7

ruslelena [56]

Answer:

Use desmos.

Step-by-step explanation:

In the image attached, I graphed the linear function on a graphing calculator. B=7 and the slope is 3.

7 0

3 years ago

In a certain city district the need for money to buy drugs is stated as the reason for 70% of all thefts. Find the probability t

torisob [31]

Answer:

9.72% probability that among the next 7 theft cases reported in this district, exactly 3 of them resulted from the need to buy drugs.

Step-by-step explanation:

For each theft, there are only two possible outcomes. Either the need to buy drugs is the reason of the theft, or it is not. Each theft is independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In a certain city district the need for money to buy drugs is stated as the reason for 70% of all thefts.

This means that $p = 0.7$

Find the probability that among the next 7 theft cases reported in this district, exactly 3 of them resulted from the need to buy drugs.

This is P(X = 3) when n = 7. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{7,3}.(0.7)^{3}.(0.3)^{4} = 0.0972$

9.72% probability that among the next 7 theft cases reported in this district, exactly 3 of them resulted from the need to buy drugs.

5 0

2 years ago

Bob,Cal,and Pete each made a stack of baseball cards.Bob's stack was 0.2 meter high.Cal's stack was 0.24 meter high.Pete's stack

AlekseyPX

Answer:

0.24 > 0.18

Step-by-step explanation:

Given that,

Bob's stack = 0.2m

Cal's stack = 0.24m

Pete's stack = 0.18m

To find?

A number sentence.

<em>A simple sentence is a string/collection of words that contain a subject and a verb whereas a number sentence is a sentence that consist of </em><em>mathematical operation</em><em> like +, -, /, * together with an equality such as =, <, >, and like a sentence it also tell a fact.</em>

<em> </em>So, the number sentence that compares cal's stack of cards to Pete's stack is

<h2>0.24 > 0.18</h2>

<em />

<em />

<em> </em>

6 0

3 years ago

Read 2 more answers

The radius of a cone is increasing at a constant rate of 7 meters per minute, and the volume is decreasing at a rate of 236 cubi

storchak [24]

Answer:

The rate of change of the height is 0.021 meters per minute

Step-by-step explanation:

From the formula

$V = \frac{1}{3}\pi r^{2}h$

Differentiate the equation with respect to time t, such that

$\frac{d}{dt} (V) = \frac{d}{dt} (\frac{1}{3}\pi r^{2}h)$

$\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (r^{2}h)$

To differentiate the product,

Let r² = u, so that

$\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (uh)$

Then, using product rule

$\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h\frac{du}{dt}]$

Since $u = r^{2}$

Then, $\frac{du}{dr} = 2r$

Using the Chain's rule

$\frac{du}{dt} = \frac{du}{dr} \times \frac{dr}{dt}$

∴ $\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h(\frac{du}{dr} \times \frac{dr}{dt})]$

Then,

$\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]$

Now,

From the question

$\frac{dr}{dt} = 7 m/min$

$\frac{dV}{dt} = 236 m^{3}/min$

At the instant when $r = 99 m$

and $V = 180 m^{3}$

We will determine the value of h, using

$V = \frac{1}{3}\pi r^{2}h$

$180 = \frac{1}{3}\pi (99)^{2}h$

$180 \times 3 = 9801\pi h$

$h =\frac{540}{9801\pi }$

$h =\frac{20}{363\pi }$

Now, Putting the parameters into the equation

$\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]$

$236 = \frac{1}{3}\pi [(99)^{2} \frac{dh}{dt} + (\frac{20}{363\pi }) (2(99)) (7)]$

$236 \times 3 = \pi [9801 \frac{dh}{dt} + (\frac{20}{363\pi }) 1386]$

$708 = 9801\pi \frac{dh}{dt} + \frac{27720}{363}$

$708 = 30790.75 \frac{dh}{dt} + 76.36$

$708 - 76.36 = 30790.75\frac{dh}{dt}$

$631.64 = 30790.75\frac{dh}{dt}$

$\frac{dh}{dt}= \frac{631.64}{30790.75}$

$\frac{dh}{dt} = 0.021 m/min$

Hence, the rate of change of the height is 0.021 meters per minute.

3 0

2 years ago

Gina wants to ride the waves at flagship pier in Galveston so she rents a surfboard for $5 per hour plus an initial or beginning

anastassius [24]

Fourteen hours. The equation is 5x+20=90. Solve for X.

5 0

2 years ago